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GarryVolchara [31]

4 years ago

8

I need help with this

1 answer:

bija089 [108]4 years ago

4 0

Answer:

$Surface\ area = 6728.3125(pi)\\\\Surface\ area = 21137.6171211$

Step-by-step explanation:

The lateral surface area of an object is the surface area of the subject excluding the base and the top of the 3-dimensional figure. The surface area of the object is the 2-dimensional space of an object, in essence, if one was going to wrap the object, the amount of material they would need to cover the object. To find the lateral surface area of a cylinder, one must find the circumference of the circle at the top of the cylinder, and then multiply it by the height of the cylinder. The circumference of a circle is the distance around it, the perimeter.

The formula one would use is,

$A_s = (pi)(r^2)(h)$

Were (pi) represent the value (3.1415...), (r) represent the radius of the base, that is the distance from the center point of the circle on the base, to the outside distance of the circle. The radius of a circle is always half of the diameter. (h) represents the height of the figure.

$A_s = (pi)(r^2)(h)\\\\= (pi)((\frac{3.5}{2})^2))(13)\\\\= (pi)(1.75)^2(13)\\\\= (517.5625)(13)(pi)\\\\=(6728.3125)(pi)\\\\= ~21137.6171211$

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7n-30 equals 4n +6 what is the value of N

Marta_Voda [28]

7n - 30 = 4n + 6

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3n = 36 / : 3

n = 12 ← the end solution

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Are the following expression equivalent? Please show your work 3xy^2/4y and 6xy^2/8xy

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3 years ago

URGENT 50 PTS AND BRAINLIEST FOR A CORRECT ANSWER THAT EXPLAINS WELL

snow_tiger [21]

Answer:

A. $(x+5)^2+(y-4)^2=16$

B. $(x-1)^2+(y-4)^2=2\\$

C. $\left(x-3\right)^2+\left(y-5\right)^2=9$

Step-by-Step Explanation:

A. Tangent to x-axis, r=4, contains (-5,8)

The equation of a circle is this: $(x-h)^2+(y-k)^2=r^2\\$

Therefore, we know that our equation will be: $(x-h)^2+(y-k)^2=4^2=16$

Because the circle is tangent to the x-axis, the point (-5,8) will be the top of the circle.

Therefore, the center is (-5,4), where -5=h and 4=k.

The answer is $(x+5)^2+(y-4)^2=16$

B. Diameter endpoints (2,5) and (0,3)

To solve for the diameter, we can use this equation: $d=\sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2 }$

$d=\sqrt{(2-0)^2+(5-3)^2 }\\\\d=\sqrt{2^2+2^2}=\sqrt{4+4} =\sqrt{8}= 2\sqrt{2}$

Because the radius is half of the diameter, $r=\sqrt{2}$

Therefore, we know that our equation will be: $(x-h)^2+(y-k)^2=(\sqrt{2}) ^2=2$

Then, we can decipher that h=1, as the midpoint of 0 and 2 is 1, and k=4, as the midpoint of 3 and 5 is 4.

The answer is $(x-1)^2+(y-4)^2=2$

C. Center on x=3, tangent to y-axis at (0,5)

We can see that the center is (3,5). Therefore, the equation is $(x-3)^2+(y-5)^2=r^2\\$

To solve for r, we can substitute the point (0,5) into the equation.

$(0-3)^2+(5-5)^2=r^2\\(-3)^2+(0)^2=r^2\\r^2=9$

The answer is $(x-3)^2+(y-5)^2=9$

<em>Hope this helped!</em>

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Elodia [21]

Answer:

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Step-by-step explanation:

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3 years ago