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lbvjy [14]
3 years ago
12

Gina has 5 2/8 feet of silver ribbon and 3 6/8 of gold ribbon. How much more silver ribbon does Gina have than gold ribbon.

Mathematics
1 answer:
Paraphin [41]3 years ago
6 0

Answer: we are simply to subtract the length of the gold ribbon which is 2 4/6 ft from the length of the silver ribbon, 5 2/6 feet. Mathematically,

                               5 2/6 feet - 2 4/6 feet = 8/3 feet

Therefore, Gina has 8/3 feet more of the silver ribbon than the golden ribbon.

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Sharla, earned 2,000 more than Paul

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Algebra expressions for 1/4 <br> the amount of salt
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1/4 x

Step-by-step explanation:

I think this because you don't know the amount of salt so that would be labeled x.

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The both that are not in green I don't know how to do them . I need some help.
attashe74 [19]

Answer:

Step-by-step explanation:

B. 0.00604

D.1.47 ×10^{-3}

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3 years ago
PLEASEEE I DONT KNOW HOW TO DO ITTTT. THE 35.8 IS RIGHT BUT I CANT GET MEASURE OF ANGLE C AND A I GOT 46.2 for A AND 70.8 for C
Rashid [163]

Answer:

Hope it helps....!!!!!

Step-by-step explanation:

AB = c = 38

BC = a = 29

AC = b

Angle ABC = 63 degrees

Solving for AC   "b":

Cosine rule: c^2 = a^2 * b^2 -2ab * cos C

38^2 = 29^2 * b^2 - (2* 29) * b * (cos 38)

1444 = 841 * b^2 - 58 * b * 0.955

(1444 + 58)/0.955 = b^2 * b

1572.77486911 = b^3

11.62935 = b

11.63 = b (rounded to two decimal places)

Now solving for angle A:

Sine rule: a/sinA = b/sinB

29/sinA = 11.63/sin(63)

sinA/29 = sin(63)/11.63

sin A = (sin(63)/11.63) * 29

sin A = 0.41731

A = sin^-1 (0.41731)

A = 24 degrees 39 minutes 53 seconds

Now solving for angle C:

Sine rule: c/sinC = b/sinB

38/sinC = 11.63/sin(63)

sinC/38 = sin(63)/11.63

sin C = (sin(63)/11.63) * 38

sin C = 0.54682

C = sin^-1 (0.54682)

C = 33 degrees 8 minutes 56 seconds

3 0
3 years ago
For one child, a childcare facility charges $350 per month for preschool and $5.00 per hour for each additional hour for after-s
Hatshy [7]

Answer:

D. 80

Step-by-step explanation:

We have the following function  :

f(h)=350+5h (I)

Where f(h) is the monthly fee for after - school care and preschool.

Where h represents the number of hours spent in after - school care.

We know that the total monthly bill for one child was $750 ⇒

f(h)=750

Using (I) we will find the value of the hours ''h'' that verifies the expression ⇒

f(h)=750=350+5h ⇒

750=350+5h\\750-350=5h\\400=5h\\h=\frac{400}{5}=80

We find that the value of the hours ''h'' is 80 hours.

The total number of hours the child spent in after - school care is D. 80

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3 years ago
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