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2 years ago

If the graph of the function y = x2 is reflected across the x-axis, what equation would correctly describe the new function

Mathematics

1 answer:

vaieri [72.5K]2 years ago

6 0

To graph the absolute value graph the function y=f(x). Anything above the x- axis, stays above it.

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Read the following poem:

pentagon [3]

Answer:

7, I believe. I have to fill in the extra character space, so I hope you have a nice day :)

6 0

2 years ago

I need help!!! ASAP!!!! !!!!!

GalinKa [24]

Answer:

Volume= 729cm^3

Height= 9cm^2

Area of Base= 81cm^2

Volume=450m^3

Height= 3m^2

Area of Base=150m^2

Volume= 480 cm^2

Area of base=75cm^2

Height= 8cm^2

Volume =120in^3

Area of Base=20in^2

Height= 6in^2

Step-by-step explanation:

Volume = (length) Times (Width) Times (Height)

Area os base = (Length) Times (width)

3 0

2 years ago

A circule has a diameter of 28 ft what is the circumference

lidiya [134]

Answer:

Circumference of a 28 Foot Diameter Circle ; 87.965, feet ; 1,055.6, inches ; 87′ 11.6″, feet and inches ; 26.812, meters ; 2,681.2, centimeters .

Step-by-step explanation:

6 0

1 year ago

Ap calc multiple choice question; attached below please explain how, please!

anygoal [31]

Answer:

C. $\frac{f(b)-f(1)}{b-1}=20$

General Formulas and Concepts:

Calculus

Mean Value Theorem (MVT) - If f is continuous on interval [a, b], then there is a c∈[a, b] such that $f'(c)=\frac{f(b)-f(a)}{b-a}$

MVT is also Average Value

Step-by-step explanation:

Step 1: Define

$f(x)=e^{2x}$

f'(c) = 20

Interval [1, b]

Step 2: Check/Identify

Function [1, b] is continuous.

Derivative [1, b] is continuous.

∴ There exists a c∈[1, b] such that $f'(c)=\frac{f(b)-f(a)}{b-a}$

Step 3: Mean Value Theorem

Substitute: $20=\frac{ f(b)-f(1)}{b-1}$
Rewrite: $\frac{ f(b)-f(1)}{b-1}=20$

And we have our final answer!

5 0

2 years ago

Function: g(x) = 2x2 – 8

DedPeter [7]

Answer:

q = 0, r = 2, s = 3, t = -3

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers