Johannes Kepler and his laws were a great influence on Isaac Newton. ... Newton used his laws of gravity and motion to derive Kepler's laws and show that the motion of the planets could be explained using mathematics and physics.
According to the information, it can be inferred that the best way to distribute the chairs and mirrors is to put the light system on a wall and put the 3 mirrors and chairs in front of the light as shown in the image.
<h3>How to distribute the objects to take advantage of the light from the bulb?</h3>
To take advantage of the light from the bulb for the three chairs and the three mirrors, the objects must be placed in such a way that all three receive enough light to be able to carry out the work of cutting the hair.
So, the best option would be to put the bulb in the middle of a wall, and place a chair and mirror in front of the bulb. The other two chairs should be located one on each side of the centered chair and the mirrors in front of each chair.
Learn more about light in: brainly.com/question/26914812
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Acceleration is any change in speed or direction of motion.
Speeding up, slowing down, or moving along a curve are all accelerations.
Answer:
7.40m/s
Explanation:
The masses of the cars with their respective initial velocities are;
![m_1 = 212kg](https://tex.z-dn.net/?f=%20m_1%20%3D%20212kg)
![u_1 = 8.00 m{s}^{ - 1}](https://tex.z-dn.net/?f=u_1%20%3D%208.00%20m%7Bs%7D%5E%7B%20-%201%7D%20)
![m_2 = 196kg](https://tex.z-dn.net/?f=m_2%20%3D%20196kg)
![u_1 =6.75m {s}^{ - 1}](https://tex.z-dn.net/?f=u_1%20%3D6.75m%20%7Bs%7D%5E%7B%20-%201%7D%20)
Since the two car stuck after collision, they all move with a common velocity in the same direction.
Let the velocity at which the two cars will be moving after collision be V.
From the conservation of momentum, in a closed system, momentum before collision is equal to momentum after collision.
Mathematically,
![m_1u_1 +m_2u_2 = (m_1 + m_2)v](https://tex.z-dn.net/?f=m_1u_1%20%2Bm_2u_2%20%3D%20%28m_1%20%2B%20m_2%29v)
By substitution, we obtain;
![(212 \times 8) +(196 \times 6.75) = (212 + 196)v](https://tex.z-dn.net/?f=%28212%20%5Ctimes%208%29%20%2B%28196%20%5Ctimes%206.75%29%20%3D%20%28212%20%2B%20196%29v)
![\implies1696+1323 =408 \times v](https://tex.z-dn.net/?f=%20%5Cimplies1696%2B1323%20%3D408%20%5Ctimes%20v)
![\implies3019 =408 \times v](https://tex.z-dn.net/?f=%20%5Cimplies3019%20%3D408%20%5Ctimes%20v)
Dividing through by 408, we obtain
![\implies\frac{3019}{408} = \frac{408 \times v }{408}](https://tex.z-dn.net/?f=%20%20%5Cimplies%5Cfrac%7B3019%7D%7B408%7D%20%3D%20%20%5Cfrac%7B408%20%5Ctimes%20v%20%7D%7B408%7D%20)
![\implies v =7.3995](https://tex.z-dn.net/?f=%20%20%5Cimplies%20v%20%3D7.3995)
Therefore,v=7.40m/s
Underhand serve is a type of volleyball serve in which a player holds the ball with one hand and swings the other hand in an arc motion, striking under the ball with a fist to put it into play. An underhand serve is the most common serve for beginners.