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laila [671]
3 years ago
11

An astronaut, while revolving in a

Physics
1 answer:
sergey [27]3 years ago
8 0

Answer:

Why the hell would he throw a spoon out like if I were in space i would little letter in . bottle and see when someone finds it (link my ph. number obviously)

Explanation:

so yea lol

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Air in a 120 km/h wind strikes head on the face of abuilding 45m wide by 75m high and is brought to rest. if air has a mass of 1
AlekseyPX
From conservation of momentum, the ram force can be calculated similarly to rocket thrust:
 F = d(mv)/dt = vdm/dt.
 <span>In other words, the force needed to decelerate the wind equals the force that would be needed to produce it. 
</span><span> v = 120/3.6 = 33.33 m/s 
</span><span> dm/dt = v*area*density
</span> dm/dt = (33.33)*((45)*(75))*(1.3) 
 dm/dt = <span> 146235.375 </span><span>kg/s 
</span><span> F = v^2*area*density
</span> F = (33.33)^2*((45)*(75))*(1.3) = <span> <span>4874025 </span></span><span>N 
</span> This differs by a factor of 2 from Bernoulli's equation, which relates velocity and pressure difference in reference not to a head-on collision of the fluid with a surface but to a fluid moving tangentially to the surface. Also, a typical mass-based drag equation, like Bernoulli's equation, has a coefficient of 1/2; however, it refers to a body moving through a fluid, where the fluid encountered by the body is not stopped relative to the body (i.e., brought up to its speed) like is the case in this problem.
4 0
3 years ago
Read 2 more answers
20 m
liubo4ka [24]

Answer:

  1.9 km​

Explanation:

The equation for vertical motion is ...

  h(t) = -4.9t^2 +26t +20

This will have a zero near t = 5.988 seconds.*

The horizontal distance traveled in that time is ...

  (310 m/s)(5.988 s) ≈ 1856 m ≈ 1.9 km

_____

* The root of a quadratic can be found numerous ways. We choose the quick and easy: let a graphing calculator show it to you.

5 0
4 years ago
On an aircraft carrier, a jet can be catapulted from 0 to 240
IRISSAK [1]

Answer:

m = 27752.7 [kg]

Explanation:

To solve this problem we must first use the following equation of kinematics.

v_{f}=v_{o}+a*t

where:

Vf = final velocity = 240 [km/h]

Vo =  initial velocity = 0

a = acceleration [m/s²]

t = time = 2 [s]

But first we must convert the speed from kilometers per hour to meters per second.

240[\frac{km}{h} ]*(\frac{1h}{3600s} )*(\frac{1000m}{1km} )=66.67[m/s]

Now replacing:

66.67 = 0 +a*2\\a = 33.33 [m/s^{2} ]

Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.

∑F = m*a

925000=m*33.33\\m = 925000/33.33\\m = 27752.7 [kg]

4 0
3 years ago
How much mass does the sun have then earth
nexus9112 [7]

Answer:

idk

Explanation:

i am tchew good

8 0
4 years ago
A ball of mass 0.7 kg flies through the air at low speed, so that air resistance is negligible. (a) What is the net force acting
Fed [463]

Answer:

A) Gravitational Force, F=-6.86N.

B) The y component of momentum.

C) The x component of momentum will remain the same.

D)The y component of momentum decreases.

E)The z component of momentum will remain constant.

Explanation:

First, let the x-axis be positive in the same direction as the horizontal speed of the ball, let the y-axis be positive in the opposite direction of gravity.

A) since there is no air resistance, the only force acting on the ball is the gravitational force. This force is downwards so it is negative. The net force is

F=-9.8*0.7=-6.86N.

B)Because the net force (and the only one) is on the y-axis, only the vertical component of the momentum will be changed due to the force.

C)Since there is no resistance of air, the ball behaves as in projectile motion problems, this means that the x component of the velocity remains constant, also does the mass. Remembering that momentum is velocity times mass, it can be easily seen that x component of momentum remains constant too.

D)The y component of momentum decreases, this is because gravity decreases the y component of the velocity.

E)Since there is no z component of the force there is no change in the z component of the momentum.

5 0
3 years ago
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