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Natali5045456 [20]
3 years ago
11

How does the force of the car change as the mass of the car is increased?

Physics
1 answer:
Nimfa-mama [501]3 years ago
5 0

yes

Explanation:

because if a car is 100 pounds then it will have less force than a 250 pound car

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A helicopter blade spins at exactly 110 revolutions per minute. Its tip is 4.50 m from the center of rotation. (a) Calculate th
NeX [460]

Answer:

(a). The average speed is 51.83 m/s.

(b). The average velocity over one revolution is zero.

Explanation:

Given that,

Angular velocity = 110 rev/m

Radius = 4.50 m

(a). We need to calculate the average speed

Using formula of average speed

v=r\omega

v = 4.50\times110\times\dfrac{2\pi}{60}

v=51.83\ m/s

(b). The average velocity over one revolution is zero because the net displacement is zero in one revolution.

Hence, (a). The average speed is 51.83 m/s.

(b). The average velocity over one revolution is zero.

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3 years ago
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The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed
galben [10]

Answer:

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒ \angle BCA = (90-30)

⇒             =60^{\circ}

then,

⇒ \angle BAC=(180-45-60)

⇒             =75^{\circ}

Now,

The corresponding angle will be:

⇒ \angle FAC=60^{\circ}

⇒ \angle FAB=70+60

⇒             =135^{\circ}

Aspect of F across the AC arm will be:

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On putting the values of F, we get

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4 0
3 years ago
Can someone help me ?
hammer [34]

Answer:

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          0 - 2 s                Constant Velocity           Increasing Velocity

          2 - 3 s                Constant Velocity           Constant Velocity

          3 - 5 s                Constant Velocity           Increasing Velocity

          5 - 6 s                Constant Velocity           Decreasing Velocity

2) For Red and Blue car y₂  = 120       v = \frac{y_{2}-y_{1}}{t_{2}-t_{1}} = \frac{120-0}{6-0} = 20 m/s

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3)   At t = 2s, the cars are the same position, and are moving at the same rate

                    Position - same

                    Velocity - same

The position-time graph shares the same spot for two cars.

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A copper bar of length h and electric resistance r slides with negligible friction on metal rails that have negligible electric
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