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faltersainse [42]
3 years ago
12

Quinn's mom went to the same middle school that Quinn is now attending. The current student population is 817 students. Since Qu

inn's mom attended, the school has experienced a
57% increase in population. About how many students were enrolled at the school when Quinn's mom attended?
Mathematics
2 answers:
djyliett [7]3 years ago
7 0

57 x 817 = 46569

46569 divided by 100 = 465.69

817-465.69 = 351.31

Answer : 351

<em>Explanation : 57 times 817 equals to 46569 and then you divided by 100 . Then it equals to 465.69 . To find out the how many more students were enrolled you have to subtract 465.69 from 817 and then you get 351.31 which you round to 351 . </em>

musickatia [10]3 years ago
4 0

Answer:

520

Step-by-step explanation:

Past number of pupils: p

Increase of 57% = 1.57

Present number of pupils = 817

p x 1.57 = 817

p = 817 divided by 1.57 = 520.382

rounded to the nearest whole number = 520 (this is why the question says "about" how many...)

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The reasons why the above selections are correct are as follows;

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<em />

Learn more about rigid transformations here:

brainly.com/question/14301866

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Bethany sent 60 text messages. She said that 15% of those messages were to her best friend. How many text messages did Bethany's
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Gertrude takes out a $5,500 subsidized Stafford loan, which must be paid back in ten years. Gertrude will graduate four years af
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Answer:

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Step-by-step explanation:

As we know the formula of per month installments

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By putting the value of P (loan applied for)=$5500

r (Monthly rate of interest) =\frac{6.8}{12\times 100}

n = number of monthly installments = 10×12 = 120

E.M.I.=\frac{5500\times (\frac{6.8}{12\times 100})(1+\frac{6.8}{1200})^{120}}{(1+\frac{6.8}{1200})^{120}-1}

=\frac{5500\times .00567\times (1+.00567)^{120}}{(1+.00567)^{120}-1}

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