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faltersainse [42]
3 years ago
12

Quinn's mom went to the same middle school that Quinn is now attending. The current student population is 817 students. Since Qu

inn's mom attended, the school has experienced a
57% increase in population. About how many students were enrolled at the school when Quinn's mom attended?
Mathematics
2 answers:
djyliett [7]3 years ago
7 0

57 x 817 = 46569

46569 divided by 100 = 465.69

817-465.69 = 351.31

Answer : 351

<em>Explanation : 57 times 817 equals to 46569 and then you divided by 100 . Then it equals to 465.69 . To find out the how many more students were enrolled you have to subtract 465.69 from 817 and then you get 351.31 which you round to 351 . </em>

musickatia [10]3 years ago
4 0

Answer:

520

Step-by-step explanation:

Past number of pupils: p

Increase of 57% = 1.57

Present number of pupils = 817

p x 1.57 = 817

p = 817 divided by 1.57 = 520.382

rounded to the nearest whole number = 520 (this is why the question says "about" how many...)

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What is the area of the composite figure? (use 3.14 for pi). Explain how you arrived at your answer. Please round to the nearest
maksim [4K]

The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

Step-by-step explanation:

The given is,

                 Given diagram is combination of Rectangle and Semi circle.

Step:1

         Res the attachment,

                      Area of given diagram = Area of A + Area of B..............(1)

Step:2

         For A,

         The A section in the given diagram is semi circle,

                     Diameter of semi circle = Total distance - ( 2+3)

                                          ( ∵ 2, 3 are top distance in the given diagram)

                                                             = 10 - 5

                                        Diameter, d = 5 cm

                                             Radius, r = \frac{d}{2}

                                                          r = \frac{5}{2}

                                                         r = 2.5 cm

                                          Area, A_{A}  = \frac {\pi r^{2} }{2}........................(2)

                                                    A_{A}  = \frac {\pi (2.5)^{2} }{2}  

                                                           = \frac {\pi ( 6.25) }{2}

                                                           = \frac{19.63}{2}

                                                     A_{A} = 9.8174 cm^{2}

Step:3

               For B,

               Area of rectangle is,

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              Where, l - Length = 10 cm

                          b - Width = 2 cm

              Equation (3) become,

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Step:4

               From the equation (1),

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Result:

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