Answer:
Which ever item has more water inside of it
Explanation:
Answer:
The muscle cell need to use most entry in a typical day
Answer:
1.10 × 10⁻¹² m
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
Speed of Light = Wavelength times Frequency
Explanation:
<u>Step 1: Define</u>
ν = 2.73 × 10²⁰ Hz
<u>Step 2: Find wavelength</u>
3.0 × 10⁸ m/s = λ(2.73 × 10²⁰ Hz)
λ = 1.0989 × 10⁻¹² m
<u>Step 3: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules.</em>
1.0989 × 10⁻¹² m ≈ 1.10 × 10⁻¹² m
Answer:
The electronengativity values of given elements is as follows.
Fluorine - 4
Chlorine -3
Bromine - 2.9
Iodine- 2.5
Explanation:
Electronegativity =consant (I.E-E.A)
The electron affinity and ionization energy values of the given elements is as follows.
(In attachment)
First we have to find the value of constant by using the fluorine atom to whom the electronengativity taken as "4".
<u>Fluorine:</u>
![4=constant[1678-(-327.8)]](https://tex.z-dn.net/?f=4%3Dconstant%5B1678-%28-327.8%29%5D)

By using this constant values we can find electronegatvity values of remaining elements.
<u>Chlorine:</u>
![Electronegativity=0.0019942168[1255+348.7]=3.1980\sim 3](https://tex.z-dn.net/?f=Electronegativity%3D0.0019942168%5B1255%2B348.7%5D%3D3.1980%5Csim%203)
Therefore, electronegativity of chlorine is 3.
<u>Bromine:</u>
![Electronegativity=0.0019942168[1138+324.5]=2.91\sim 2.9](https://tex.z-dn.net/?f=Electronegativity%3D0.0019942168%5B1138%2B324.5%5D%3D2.91%5Csim%202.9)
Therefore, electronegativity of bromine is 2.9.
<u>Iodine:</u>
![Electronegativity=0.0019942168[1007+295.7]=2.59\sim 2.5](https://tex.z-dn.net/?f=Electronegativity%3D0.0019942168%5B1007%2B295.7%5D%3D2.59%5Csim%202.5)
Therefore, electronegativity of iodine is 2.5.