Explain how you determined which water use was larger.

Calculate Î”HÂ° = for the chemical reaction

babymother [125]

Answer: $\Delta H^0$ for the reaction $Cl_2(g)+F_2(g)\rightarrow 2ClF(g)$ is -108kJ

Explanation:

The balanced chemical reaction is,

The expression for enthalpy change is,

$\Delta H=[n\times B.E_{reactants}]-[n\times B.E{products}]$

where, n = number of moles

Now put all the given values in this expression, we get

$\Delta H=[1\times B.E_{Cl_2}+1\times B.E_{F_2}]-[2\times B.E_{ClF}]$

$\Delta H=[(1\times 243)+(1\times 159)]-[2\times 255]$

$\Delta H=-108kJ$

Thus $\Delta H^0$ for the reaction $Cl_2(g)+F_2(g)\rightarrow 2ClF(g)$ is -108kJ

4 0

2 years ago

What is the percent by mass of water in Na2SOa 10H20?total mass of element in compoundUse%Elementx 100molar mass of compoundO 5.

wlad13 [49]

Molar mass Na₂SO₄. 10H₂O = 322.19 g/mol

Molar mass H₂O = 18.0

% Element = molar mass / total mass x 100

% Element = 18 / 322,19 x 100

% Element = 5.59 %

Answer A

hope this helps!

6 0

2 years ago

How do ethical concerns affect scientific research

Gwar [14]

Answer:

Ethical concerns affect scientific research by adding boundaries to what can and cant be experimented on. An example is that its socially unacceptable to experiment on humans because its considered wrong and horrific, even at the expense of learning more about human nature and/or the human body.

7 0

2 years ago

Old oceanic crust is more dense than new oceanic crust because

grin007 [14]

Oceanic crust would be on top, being less dense and doesn't have as much water in it. Old oceanic crust is usually on the bottom, and filled with water. It is more dense.

3 0

2 years ago

How would you make a 2.00L of 0. 500M sodium chloride solution. (assume you have a fully equipped lab with water); sketch, calc

Gwar [14]

Answer:

Sodium chloride solution:

First you need to calculate the mass of salt needed (done in the explanation), which is 58.44g. Then it have to be weighted in an analytical balance in a weighting boat and then transferred into a 2L volumetric flask that is going to be filled until the mark with distilled water.

Sulfuric acid dilution:

First you need to calculate the volume needed (done in the explanation), it is 16.6 mL. Using a graduated pipette one measures this volume and transfer it into a 2L volumetric flask that is already half filled with distilled water, and then one fills it until its mark.

Explanation:

Sodium chloride solution:

Each liter of a 0.500M solution has half mol, so 2L of said solution has 1 mol of salt. Sodium chloride molar mass is 58.44g/mol, so in 2L of solution there is 58.44g of salt. That`s the mass that`s going to be weighted and transferred to a 2L volumetric flask.

Sulfuric acid dilution:

This is the equation for dilution of solutions:

$c_{1} v_{1} =c_{2} v_{2}$

Where "c1" stands for the initial concentration (stock solution concentration), "v1" for the initial volume (volume of stock solution used), "c2" for the desired concentration and "v2" for the desired volume.

When we are diluting from a stock solution we want to know how much do we have to pipette from the stock solution into our volumetric flask. We do so by isolating the "v1" term from the dilution equation:

$v_{1} =\frac{c_{2} v_{2} }{c_{1} }$

in this case that would be:

$v_{1} =\frac{0.100 x2.0 }{12.0 }=0.0166L=16.6mL$

5 0

2 years ago