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WARRIOR [948]
3 years ago
6

Which situation can be modeled by the inequality m > 225? A. The community theater's auditorium can seat at most 225 people.

B. The number of people who attended the mathematics conference was more than 225. C.The students need to raise at least $225 in order to pay for the bus ride to go on a field trip. D. The distance Deshawn must travel from his house to reach the Gulf Coast is less than 225 miles.
Mathematics
1 answer:
Georgia [21]3 years ago
6 0

Answer:

<h3>B. The number of people who attended the mathematics conference was more than 225.</h3>

Step-by-step explanation:

Given the inequality m > 225, the inequality means that m is greater than 225. Since the inequality sign does not include equal to sign, then the value of m cannot be less than and equal to 225. The situation that best fits the expression based on the explanation above is "The number of people who attended the mathematics conference was more than 225"

Emphasis should be on 'WAS MORE THAN' according to the statement. The greater sign means that the number of people will always be greater than or more than 225 representing the variable <em>m as the number of people.</em>

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Christian is planning a vacation and finds an airplane ticket that cost 180$. He found a promo code offering 17% off. Write a si
lesya [120]

Answer:

83/100 x 180

Step-by-step explanation:

We have to find the cost of the ticket after the discount.

100% - 17%= 83%

83% of the total percentage of the original price that he needs to pay.

So we do:

83/100 x 180

So, this would be the expression.

Hope this helps!:)

7 0
3 years ago
How many "words" can be written using exactly five A's and no more than three B's (and no other letters)?
kakasveta [241]

This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.

Case 1: Five A's and One B

Total number of letters = 6

Total number of words possible = \frac{6!}{5!*1!}=6

Case 2: Five A's and Two B's

Total number of letters = 7

Total number of words possible = \frac{7!}{5!*2!}=21

Case 3: Five A's and Three B's

Total number of letters = 8

Total number of words possible = \frac{8!}{5!*3!}=56

Total number of possible words will be the sum of all three cases.

Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83

8 0
3 years ago
Read 2 more answers
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Darya [45]
Sorry no I’m only in 8th :(
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3 years ago
one of the angle of a triangle is 60^g and greater of the remaining angles exceeds the smaller by 26^o . find all the angles in
Firlakuza [10]

Answer:

hope this helped you

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7 0
3 years ago
A plane left on time at 12pm and arrived at 8:16 the same day which was 16 minutes late. How seconds did the plane fall behind e
astra-53 [7]
30 seconds every 15 minutes.
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5 0
3 years ago
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