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svlad2 [7]
3 years ago
10

PLEASE HELP ASAP WITH ALGEBRA!!! CORRECT ANSWER ONLY PLEASE!!! Graph g(x) = 3x^2 - 12x - 3.

Mathematics
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer:

That looks like this


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Mnenie [13.5K]
90 minus 35 = 55 Cause that is a right angle which = 90 degrees
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Please help on this one
kirill115 [55]
You just multiply g(x) and f(x) together and it gives you C :)
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3 years ago
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The manager of an accounting department wants to form a two
Y_Kistochka [10]

Answer: 153

Step-by-step explanation:

When we have a group of N elements, the total number of combinations of K elements ( K ≤ N) is:

C (N, K) = \frac{N!}{(N-k)!*K!}

Where N! = N*(N - 1)*(N - 2)*...*2*1

In this case, we have a group of 18 people (then N = 18) and we want to see how many different combinations of 2 we can make (K = 2).

Using the above equation we get:

C(18, 2) = \frac{18!}{(18 - 2)!*2!}  = \frac{18!}{16!*2!} = \frac{18*17}{2}  = 9*17 = 153

There are 153 different ways in which the manager can do this.

5 0
3 years ago
Find a particular solution to<br> y′′+6y′+5y=18te^(2t).
Andreas93 [3]

Answer:

idk just google it :)

Step-by-step explanation:

1. google it

6 0
4 years ago
In a triangle ABC, AD is drawn perpendicular to BC. <br> Prove that AB2 - BD2 = AC2 - CD2.
Finger [1]

Answer:

Given: In triangle ABC , AD is drawn perpendicular to BC.

Since AD is drawn perpendicular to BC, it creates two right triangles: ADB and ADC.

Prove that: AB^2-BD^2 = AC^2-CD^2

Pythagoras triangle for right angle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.

In a right angle triangle ADB;

AD^2+BD^2 = AB^2                 [By Pythagoras theorem]

or

AD^2= AB^2-BD^2                      .......[1]

Now, in right angle triangle ADC;

AD^2+CD^2 = AC^2                [By Pythagoras theorem]

or we can write this as;

AD^2= AC^2-CD^2                    ......[2]

Substituting the equation [1] in [2] we get;

AB^2-BD^2 =AC^2-CD^2            hence proved!

5 0
3 years ago
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