If the perimeter of the equilateral triangle is 18 cm then the width of the rectangle be 11.2 cm.
Given that the perimeter of the equilateral triangle be 18 cm and the perimeter of all the three triangles be 46.4 cm.
We are required to find the width of the rectangle.
Rectangle is basically the shape which is having opposite sides equal to each other.
Perimeter of equilateral triangle=3 *side
3* side=18
side=18/3
side=6
Since it is on the length of the rectangle so the length of rectangle be
6 cm.
Perimeter of all the three triangles=2*width of the rectangle+1 length+perimeter of 1 equilateral triangle.
T1 and T2 are the other triangles.
Suppose the width of the rectangle be x.
Perimeter=2*x+6+18
46.4=2x+24
2x=46.4-24
2x=22.4
x=11.2
So,the width of the rectangle is equal to 11.2 cm.
Hence if the perimeter of the equilateral triangle is 18 cm then the width of the rectangle be 11.2 cm.
Learn more about perimeter at brainly.com/question/19819849
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Answer:
Step-by-step explanation:
Domain= All real numbers. To get this answer i just plug the x-values into the quadratic formula to get the y-output.
Maximum area=1323/8
Range= y<= 1323/8
Answer:
1/5
Step-by-step explanation:
1/5
2/3+3/3+4/3
=2/5*3/6
= 1/5
I'm not sure.
Answer:
Monday:
<em>Cups</em><em> </em><em>of</em><em> </em><em>Sugar</em><em>:</em><em> </em><em>3</em>
<em>Tablespoon</em><em> </em><em>of</em><em> </em><em>Butter</em><em>:</em><em> </em><u><em>3</em><em>0</em></u>
<em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>Bananas</em><em>:</em><em> </em><u><em>7</em><em>5</em></u>
Wednesday
<em>Cups</em><em> </em><em>of</em><em> </em><em>Sugar</em><em>:</em><em> </em><u><em>1</em><em>.</em><em>1</em><em>2</em></u>
<em>Tablespoons</em><em> </em><em>of</em><em> </em><em>Butter</em><em>:</em><em> </em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em>
<em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>Bananas</em><em>:</em><em> </em><em>2</em><em>8</em>
