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EastWind [94]
3 years ago
5

In order to play on the 7th grade basketball team you must buy a team uniform. Last year a uniform cost $40, but this year a uni

form cost $48. What is the percent of change?
Show your work here:
INCLUDE ANSWER AND TY
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0

Answer:

20%

Step-by-step explanation:

The uniform cost $8 more than last year.

Last year was $40

Find what percent of 40 is 8.

8/0.4 = 20

the percent change is 20%

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Fill in the blank. Give O below, you can conclude that DF is congruent to _____.
lakkis [162]

Answer:

B. BC

Step-by-step explanation:

4 0
3 years ago
A student working on a report about mathematicians decides to find the 98% confidence interval for the difference in mean age at
balandron [24]

Answer:

The entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used.

Step-by-step explanation:

A student working on a report about mathematicians decides to find the 98% confidence interval for the difference in mean age at the time of math discovery for Greek mathematicians versus Egyptian mathematicians. The student finds the ages at the time of math discovery for members of both groups, which include all Greek and Egyptian mathematicians, and uses a calculator to determine the 98% confidence interval based on the t distribution, <u>the entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used.</u> There is no as such explanation of this scenario, its just the answer mentioned above.

6 0
3 years ago
Verify a ÷ b ≠ b ÷ a , if a = −3/4 and b = 4/5
Shalnov [3]

Given:

a=-\dfrac{3}{4}

b=\dfrac{4}{5}

To verify:

a\div b\neq b\div a

Solution:

We have,

a=-\dfrac{3}{4}

b=\dfrac{4}{5}

Now,

a\div b=\dfrac{a}{b}

a\div b=\dfrac{-\dfrac{3}{4}}{\dfrac{4}{5}}

a\div b=-\dfrac{3}{4}\times \dfrac{5}{4}

a\div b=-\dfrac{15}{16}               ...(i)

And,

b\div a=\dfrac{b}{a}

b\div a=\dfrac{\dfrac{4}{5}}{-\dfrac{3}{4}}

b\div a=\dfrac{4}{5}\times (-\dfrac{4}{3})

b\div a=-\dfrac{16}{15}               ...(ii)

From (i) and (ii), it is clear that

a\div b\neq b\div a

Hence verified.

5 0
3 years ago
Pls need help asap!!!
Sloan [31]

Trigonometry is the branch of mathematics that studies the relationship between the sides lengths and angles in a triangle.

<h3>What is trigonometry?</h3>

Your information is incomplete as the triangles aren't given. Therefore, an overview will be given.

It should be noted that trigonometry simply means the branch of mathematics that is concerned with angles and their application to calculation.

In this case, studies the relationship between the sides lengths and angles in a triangle. The there basic functions in trigonometry are sine, cosine, ad tangent.

Learn more about trigonometry on:

brainly.com/question/24236629

8 0
3 years ago
I’m stuck... any one able to help?<br> X^4 + 5x^3 + 3x/x
Leni [432]

Answer:

x^3+5x^2+3x

Step-by-step explanation:

1) divide each term in the numerator by the term in denominator:

(remember when dividing subtract the smaller exponent from larger exponent

for example: \frac{x^a}{x^b} say a is the larger exponent, do x^a^-^b

x^4/x=x^3

5x^3/x=5x^2

3x^2/x=3x

so

x^3+5x^2+3x

hope this helps!

6 0
3 years ago
Read 2 more answers
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