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3 years ago

Find the measure of angle R to the nearest tenth

Mathematics

2 answers:

Sonbull [250]3 years ago

8 0

The angles add up to 180°
59+39=98
180-98=82°

Alex3 years ago

4 0

Answer:

Step-by-step explanation:

I am going to use the sin law to find the angle R. Applying sin law we have that

$\frac{sin(90)}{58} = \frac{sin(R)}{37}$ , then

$sin(R) = \frac{sin(90)*37}{58} = \frac{37}{58} = 0.6379$

$R = sin^{-1}(0.6379) = 39.63\textdegree = 39.6\textdegree$ .

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Translate the description as an algebraic expression:<br>the square of the ratio of 11 and k

damaskus [11]

Answer:

The given description is equivalent to the algebraic expression,

$(\frac {11}{k})^{2}$

Step-by-step explanation:

The given description is ,

'The square of the ratio of 11 and k'

which is equivalent to the algebraic expression,

$(\frac {11}{k})^{2}$

6 0

3 years ago

A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

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3 years ago

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andrew-mc [135]

Answer:

The answer is B.

Step-by-step explanation:

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4 years ago

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Step-by-step explanation:

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3 years ago

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Katyanochek1 [597]

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Step-by-step explanation:

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4 years ago

Read 2 more answers