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fenix001 [56]
3 years ago
12

8(y - 5 ) is equivalent to which following?​

Mathematics
1 answer:
ladessa [460]3 years ago
7 0

Answer:

8y-40

Step-by-step explanation:

First you expand the brackets

8 x y - 8 x 5

= 8y - 40

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Help ! Please ! If a/2 - b/3=1 , what is 2a+3v in terms of b?
ArbitrLikvidat [17]
A/2-b/3=1  solve for a, add b/3 to both sides

a/2=1+b/3 which is equal to

a/2=(3+b)/3  multiply both sides by 2

a=(6+2b)/3  now you can substitute this into 2a+3b giving you:

2(6+2b)/3 + 3b which is equal to

(12+4b+9b)/3

(13b+12)/3
7 0
3 years ago
At the train station, the cost for parking is based on an hourly fee. Patrons that park for 2 hours or less are charged at the s
Aleksandr-060686 [28]

Answer:

96

Step-by-step explanation:

6 0
2 years ago
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Tank a has a capacity of 9.5 galloons 6 1/3 gallons of the tanks water are poured out how many gallons of water are left in the
Alisiya [41]
= 9 \frac{1}{2} - 6 \frac{1}{3} \\ = 9 \frac{3}{6} - 6 \frac{2}{6}
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3 1/6 gallons of water are left in the tank.
3 0
3 years ago
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What are some things you like about science, or about science experiments?
liraira [26]
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6 0
3 years ago
What is the area (in square units) of the region under the curve of the function f(x)=x+3, on the interval from x=1 to x=3 ?
aleksandrvk [35]

Answer:

10 square units

Step-by-step explanation:

We want to find the area under the curve f(x)=x+3 from x=1 to x=3.

We use definite integrals to find this area.

\int\limits^3_1 {x+3} \, dx

We integrate to obtain:

\frac{x^2}{2}+3x|_1^3

We evaluate the limits to get:

\frac{3^2}{2}+3(3)-(\frac{1^2}{2}+3(1))

4.5+9-0.5-3=10

Therefore the area under the curve from x=1 to x=3 is 10 square unit.

8 0
3 years ago
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