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Katyanochek1 [597]
3 years ago
10

PLEASE HELP

Mathematics
1 answer:
Semenov [28]3 years ago
6 0

Answer:

\sum\limits^7_{n=1}(4n - 3)

Step-by-step explanation:

Given

1 + 5 + 9 + .....

Required

Write a definition

First, we derive a formula for the series using:

T_n = a + (n - 1)d

From the attached data;

a = 1

d = 5 - 1 = 4

So:

T_n = a + (n - 1)d

T_n = 1 + (n - 1) * 4

T_n = 1 + 4n - 4

Collect like terms

T_n = 4n - 4+1

T_n = 4n -3

So, the definition for first 7 terms is:

\sum\limits^7_{n=1}(4n - 3)

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olchik [2.2K]

Answer:

No..... who's that's

Step-by-step explanation:

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5 0
3 years ago
How much fertelizer is needed for a 180 square-foot garden
Fed [463]

Answer:

6 pounds of fertilizers are needed for garden area of 180 square foot.

Step-by-step explanation:

Let 'x' pounds of fertilizers be needed for 180 square foot garden.

Given:

4 pounds of fertilizer needed for an area of 120 square foot.

The area of the garden given is 180 square foot.

Now, as per question:

4 pounds of fertilizer is equivalent to an area of 120 square foot.

Therefore, 'x' pounds of fertilizer is equivalent to an area of 180 square foot.

Applying proportion and cross multiplying method, we get:

x            4

_      =    _

180        120

120x=4 x 180

120x= 720

x = 720

      _

     120

x=6 LBS

Therefore, 6 pounds of fertilizers are needed for garden area of 180 square foot.

Step-by-step explanation:

8 0
2 years ago
Compute the critical value z Subscript alpha divided by 2 that corresponds to a 86​% level of confidence.
tester [92]

Answer:

z = 1.476

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.86}{2} = 0.07

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.07 = 0.93, so z = 1.476

The answer is z = 1.476

7 0
3 years ago
What is the sum of the distances of R to Q and P to Q?
Shalnov [3]

The sum of the distances of R to Q and P to Q is 9 units.

Solution:

Given points are P(–3, 6), Q(3, 6) and R(3, 3).

Distance between two points formula:

   \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance from R to Q:

Here x_1=3, y_1=3, x_2=3, y_2=6

Substitute these in the given formula, we get

Distance = \sqrt{(3-3)^2+(6-3)^2}  

               =\sqrt{0+9}

               = 3 units

Distance from R to Q is 3 units.

Distance from P to Q:

Here x_1=-3, y_1=6, x_2=3, y_2=6

Substitute these in the given formula, we get

Distance = \sqrt{(3-(-3))^2+(6-6)^2}  

               =\sqrt{36+0}

               = 6 units

Distance from P to Q is 6 units.

Sum of the distances = 3 + 6 = 9 units

Hence the sum of the distances of R to Q and P to Q is 9 units.

4 0
3 years ago
B(2x-1)-3b(x) if b(m)=2m^2+m-1
Keith_Richards [23]

Answer: cot (3x) , x=2 pi over 3

Step-by-step explanation:

6 0
3 years ago
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