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sergiy2304 [10]
3 years ago
14

Which best describes a semidiurnal tide pattern??? A) Two high tides and two low tides each day B) Two high tides and two low ti

des each month C) Two high tides and two low tides each season D) Two high tides and two low tides each year
Biology
2 answers:
Ivenika [448]3 years ago
4 0

Answer: A) Two high tides and two low tides each day

Explanation:

The tide is phenomena of periodic up and fall of the sea water that is developed by the gravitational forces by the sun and the moon also by the rotation of the earth. Two high tides and low tides occurs frequently in most places of the ocean this phenomena is called as semidiurnal tide. The semidiurnal tides occur in the ocean at intervals of 12\frac{1}{2} hours.      

GarryVolchara [31]3 years ago
3 0
A) two ugh rides and two low rides
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All of the following are major functions of proteins except 1.control of biochemical reactions. 2.support for organs or tissues.
Galina-37 [17]

Answer:

<h2>5.storage of energy</h2>

Explanation:

  • Proteins are important biomolecules that are a type of macromolecule.
  • This macromolecule is made up of a monomer that is called amino acid.
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3 years ago
In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s
lesya692 [45]

Answer:

A) 47; B) 33; C) 272; D) 122

Explanation:

The three genes are linked.

The female with withered wings and a smooth abdomen has the genotype whd sm sp+/whd sm sp+.

The male with a speck body has the genotype whd+ sm+ sp/whd+ sm+ sp.

Both individuals are homozygous for all genes, so each of them only produces one type of gamete. The resulting F1 therefore has the genotype whd sm sp+/ whd+ sm+ sp, heterozygous for all genes and with a wild-type phenotype.

The females of the F1 were mated with homozygous recessive males (test cross): whd sm sp/whd sm sp.

<h3>A)</h3>

If we assume interference is 0, the probability of crossing over happening between the genes whd and sm is independent from the probability of crossing over happening between sm and sp.

The distance = frequency of recombination × 100, so the frequency of recombination (RF) between genes whd and sm is 0.305 and the RF between genes sm and sp is 0.155.

<u>The expected double crossover progeny among the 1000 offspring will be:</u>

RF whd-sm × RF sm-sp  × 1000 =

0.305  × 0.155 × 1000 = 47 individuals will be double crossover.

<h3>B)</h3>

Interference is 0.3

The interference is calculated as 1- coefficient of coincidence (cc).

cc = observed double crossover/expected double crossover

Therefore:

I = 1 - cc

cc = 1 - I

<u>cc = 0.7</u>

Observed DCO / 47 = 0.7

Observed DCO = 0.7  × 47

Observed DCO ≅ 33

<h3>C)</h3>

The parental gametes are whd sm sp+ and whd+ sm+ sp (the genotype of the F1 female is known).

Looking at them and at the gene map we can tell that the gametes that give rise to withered wings, speck body (whd sm+ sp) and smooth abdomen (whd+ sm sp+) phenotypes are the result of recombination occurring between genes whd and sm.

To calculate the expected number of individuals with those phenotypes among the 1000 progeny we need to determine the frequency of recombination between the genes whd and sm considering there's interference.

The distance whd-sm = RF x 100

The recombination frequency is the sum of the single crossover between whd and sm and the double crossovers.

The frequency of DCO is 33/1000=0.033.

Distance whd-sm/ 100 = SCOwhd-sm + DCO

0.305 - 0.033 = SCO whd-sm

<u>Frequency of SCO whd-sm= 0.272</u>

And the expected number of individuals with those phenotypes will be 0.272 x 1000 = 272.

<h3>D)</h3>

The gametes that originate the phenotypes withered wings, speck body, smooth abdomen (whd sm sp) and wild type (whd+ sm+ sp+) are the result of recombination between genes sm and sp.

Distance sm-sp/ 100 = SCOsm-sp + DCO

0.155 - 0.033 = SCOsm-sp

<u>Frequency of SCO sm-sp= 0.122</u>

And the expected number of individuals with those phenotypes will be 0.122 x 1000 = 122.

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3 years ago
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The greenhouse and enhanced greenhouse effects refer to the return of approximately ______ percent and greater than ______ perce
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Answer:

The greenhouse and enhanced greenhouse effects refer to the return of approximately <u>80</u> percent and greater than <u>80</u> percent of the heat radiated by Earth.

Explanation:

During natural greenhouse effect :

. Solar radiation reaches the earth

. Re-radiation of heat occurs

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Hence the greenhouse effect refers to return of 80% of heat radiated by Earth.

While during Human Enhanced Greenhouse effect :

. Solar radiation reaches earth

. Re-radiation of heat occurs

. More re-emitted heat

. Less heat escapes into space

Hence the enhanced greenhouse effect refers to return of more than 80% of heat radiated by Earth .

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3 years ago
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