All categories

3 years ago

Which is bigger 4/7 or 3/5

Mathematics

2 answers:

romanna [79]3 years ago

8 0

3/5 is bigger because 4/7 = 20/35 and 3/5 = 21/35

alekssr [168]3 years ago

4 0

3/5 is bigger because if you cross multiply 4/7 with 3/5 3/5 gets 21 and 4/7 gets 20

You might be interested in

The time it takes you to go a certain distance varies inversely with the speed of travel. Suppose it takes you 4 hours to get to

fgiga [73]

$\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------$

$\bf \textit{time it takes varies inversely with the speed rate}\qquad \stackrel{time}{t}=\cfrac{k}{\stackrel{rate}{r}}
\\\\\\
\textit{we also know that }
\begin{cases}
t=\stackrel{hrs}{4}\\
r=\stackrel{mph}{50}
\end{cases}\implies 4=\cfrac{k}{50}\implies 200=k
\\\\\\
\boxed{t=\cfrac{200}{r}}
\\\\\\
\textit{if your rate r = 40, what is your distance \underline{t}?}\qquad t=\cfrac{200}{40}$

3 0

2 years ago

A newspaper and three hot chocolates cost $7. Two newspapers and two hot chocolates cost $6. How much does one hot chocolate cos

pochemuha

Answer:

the cost of one hot chocolate is $2.

Step-by-step explanation:

Let x be the hot chocolate cost and y be the newspaper cost.

Given:

A newspaper and three hot chocolates cost $7

So, the equation is

$3x+y=7$ --------(1)

Two newspapers and two hot chocolates cost $6

So, the second equation is.

$2x+2y=6$ ---------(2)

Find one hot chocolate cost?

Solve equation 1 for y.

$3x+y=7$

$y=7-3x$

Put y value in equation 2

$2x+2(7-3x)=6$

$2x+14-6x=6$

$14-4x=6$

$-4x=6-14$

$-4x=-8$

negative sign is cancelled both side.

$x=\frac{8}{4}$

$x=2$

Therefore, the cost of one hot chocolate is $2.

3 0

2 years ago

Solve the following differential equation: (2x+5y)dx+(5x−4y)dy=0 *Hint: they are exact<br><br> C=.

Tpy6a [65]

Answer with Step-by-step explanation:

The given differential equation is

$(2x+5y)dx+(5x-4y)dy=0$

Now the above differential equation can be re-written as

$P(x,y)dx+Q(x,y)dy=0$

Checking for exactness we should have

$\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}$

$\frac{\partial P}{\partial y}=\frac{\partial (2x+5y)}{\partial y}=5$

$\frac{\partial Q}{\partial x}=\frac{\partial (5x-4y)}{\partial x}=5$

As we see that the 2 values are equal thus we conclude that the given differential equation is exact

The solution of exact differential equation is given by

$u(x,y)=\int P(x,y)dx+\phi(y)\\\\u(x,y)=\int (2x+5y)dx+\phi (y)\\\\u(x,y)=x^2+5xy+\phi (y)$

The value of $\phi (y)$ can be obtained by differentiating u(x,y) partially with respect to 'y' and equating the result with P(x,y)

$\frac{\partial u}{\partial y}=\frac{\partial (x^2+5xy+\phi (y)))}{\partial y}=Q(x,y))\\\\5y+\phi '(y)=(5x-4y)\\\\\phi '(y)=5x-9y\\\\\int\phi '(y)\partial y=\int (5x-9y)\partial y\\\\\phi (y)=5xy-\frac{9y^2}{2}\\\\\therefore u(x,y)=x^2+10xy-\frac{9y^2}{2}+c$

5 0

3 years ago

A researcher found a study relating the value of a car, y, to the age of the car, x. When researchers looked at the association

vredina [299]

Answer: c) About 16% of the variation in value of the car is explained by a linear relationship with the age of the car.

e) The correlation coefficient, r, is 0.397.

Step-by-step explanation:

Given that:

Coefficient of determination (r²) between two variables, age of car (x) and value of car (y) = 0.158

Correlation of determination (r²) of 0.158 = (0.158 × 100% = 15.8% of the variation between the two variables can be explained by the regression line). Hence, about 16% of the variation between age and value of car can be explained by the linear relationship.

Coefficient of correlation (r) = sqrt(r²) = sqrt(0.158) = 0.397

8 0

3 years ago

What are the roots of the function f(x) = x2 + 2x – 1? a. x = ± √ _ 2 b. x = − 1 ± √ _ 2 c. x = 2 ± √ _ 2 d. x = 1 ± √ _ 2

Masteriza [31]

Step-by-step explanation:

Root of the function, where y = 0

f(x) = x² + 2x - 1

0 = x² + 2x - 1

x² + 2x - 1 = 0

x² + 2x = 1

x² + 2x + 1 = 1 + 1

(x + 1)² = 2

x + 1 = ±√2

x = -1 ± √2

Roots → x = -1 ± √2

7 0

2 years ago