Question

What is an equation of the line that passes through the points (-3, -2)(−3,−2) and (3, 6)(3,6)? Put your answer in fully reduced form.

Answer 1

Answer:

The equation of the line is y = $\frac{4}{3}$ x + 2

Step-by-step explanation:

The form of the equation that passes through two points (x1, y1) and (x2, y2) is y = m x + b, where

• m is the slope of the line whose rule is $m=\frac{y2-y1}{x2-x1}$

• b is the y-intercept, you can find it by substituting x, y in the equation by (x1, y1) OR (x2, y2)

Let us solve the question:

∵ The line passes through the points (-3, -2) and (3, 6)

∴ x1 = -3 and x2 = 3

∴ y1 = -2 and y2 = 6

→ Use the rule of m to find it

∵ $m=\frac{6-(-2)}{3-(-3)}=\frac{6+2}{3+3}=\frac{8}{6}$

→ Simplify it by dividing up and down by 2

∴ m = $\frac{4}{3}$

→ Substitute its value in the form of the equation above

∴ y = $\frac{4}{3}$ x + b

→ To find b substitute x and y by x1 and y1

∴ -2 = $\frac{4}{3}$ (-3) + b

∴ -2 = -4 + b

→ Add 4 to both sides

∴ -2 + 4 = -4 + 4 + b

∴ 2 = b

→ Substitute it in the form of the equation

∴ y = $\frac{4}{3}$ x + 2

∴ The equation of the line is y = $\frac{4}{3}$ x + 2