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MAXImum [283]
3 years ago
5

Can someone please help me understand how to solve this? I can't seem to wrap my head around this concept so if someone could po

ssibly explain it to me or refer me to a great resource I'd be very thankful. Thank you!

Mathematics
1 answer:
iogann1982 [59]3 years ago
5 0

Step-by-step explanation:

Hi!

So, this is peicewise function. That means that x values have to be in a certain range in order to have a function. Look at this piecewise function, for example:

\left \{ {{7x+2       } \atop {x=2}} \right. { {{x=2} \atop {x=13}} \right.

When x is 2, you use the equation 7x+2.

When x is 13, you use the equation x=2.

Now we can use this graph to figure out the definition by looking at the points. An open circle means that a point can't reach that point (less than or greater than). A closed circle means that a point <em>can </em> touch there( less than or equal to and greater than or equal to).

So here, we have a closed circle at (-1, 1) and an open circle at (-1,2).

So, for all points that are less than or equal to -1, there will be a specific equation.

For all points greater than -1, there will be a different equation.

{this is based on x-values, btw}

So let's use these points to figure out the equations.

Check 2x + 2.

2(-1) + 2

-2 + 2 =0

This doesn't work.

Check 2x + 4

2 (-1) +4

-2 + 4 =2

This doesn't work.

Check x-2

-1-2 = -3

This doesn't work.

Check x + 2

-1 + 2 = 1

This works. Therefore, we can say that D is the answer.

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Help, this is so confusing.
Mnenie [13.5K]

Answer:

D. $0.05

Step-by-step explanation:

Don't worry! I'll help you through it.

So we just have to find the unit rate (price) per apple.

$4 divided by 5lbs bag = $0.80 so, The 1st bag is $0.80 an apple.

$6 bag divided by 8lb = $0.75 an apple.

Now, simply subtract

0.80

-0.75

0.05

So your answer is D, $0.05

Have a great day!

~PumpkinSpice1

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What is the equation of a parabola with a directrix of y=2 and a focus point of 0,-2
KiRa [710]
Hope this helped. :)

Any point, <span><span>(<span><span>x0</span>,<span>y0</span></span>)</span><span>(<span><span>x0</span>,<span>y0</span></span>)</span></span> on the parabola satisfies the definition of parabola, so there are two distances to calculate:

<span>Distance between the point on the parabola to the focusDistance between the point on the parabola to the directrix</span>

To find the equation of the parabola, equate these two expressions and solve for <span><span>y0</span><span>y0</span></span> .

Find the equation of the parabola in the example above.

Distance between the point <span><span>(<span><span>x0</span>,<span>y0</span></span>)</span><span>(<span><span>x0</span>,<span>y0</span></span>)</span></span> and <span><span>(<span>a,b</span>)</span><span>(<span>a,b</span>)</span></span> :

<span><span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span><span>(<span><span>y0</span>−b</span>)</span>2</span></span><span>‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾</span>√</span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span><span>(<span><span>y0</span>−b</span>)</span>2</span></span></span>

Distance between point <span><span>(<span><span>x0</span>,<span>y0</span></span>)</span><span>(<span><span>x0</span>,<span>y0</span></span>)</span></span> and the line <span><span>y=c</span><span>y=c</span></span> :

<span><span><span>∣∣</span><span><span>y0</span>−c</span><span>∣∣</span></span><span>| <span><span>y0</span>−c</span> |</span></span>

(Here, the distance between the point and horizontal line is difference of their <span>yy</span> -coordinates.)

Equate the two expressions.

<span><span><span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span><span>(<span><span>y0</span>−b</span>)</span>2</span></span><span>‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾</span>√</span>=<span><span>∣∣</span><span><span>y0</span>−c</span><span>∣∣</span></span></span><span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span><span>(<span><span>y0</span>−b</span>)</span>2</span></span>=<span>| <span><span>y0</span>−c</span> |</span></span></span>

Square both sides.

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Expand the expression in <span><span>y0</span><span>y0</span></span> on both sides and simplify.

<span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span>b2</span>−<span>c2</span>=2<span>(<span>b−c</span>)</span><span>y0</span></span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span>b2</span>−<span>c2</span>=2<span>(<span>b−c</span>)</span><span>y0</span></span></span>

This equation in <span><span>(<span><span>x0</span>,<span>y0</span></span>)</span><span>(<span><span>x0</span>,<span>y0</span></span>)</span></span> is true for all other values on the parabola and hence we can rewrite with <span><span>(<span>x,y</span>)</span><span>(<span>x,y</span>)</span></span> .

Therefore, the equation of the parabola with focus <span><span>(<span>a,b</span>)</span><span>(<span>a,b</span>)</span></span> and directrix <span><span>y=c</span><span>y=c</span></span> is

<span><span><span><span>(<span>x−a</span>)</span>2</span>+<span>b2</span>−<span>c2</span>=2<span>(<span>b−c</span>)</span>y</span></span>

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