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4 years ago

3(4x+5)=33 5(x/2+3)=35 2(x/4+8)=18 4(2x/3+8)=40 6(3x/2-4)=30

1 answer:

6 0

3(4x+5)=33
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
3(20x)=33
60x=33
60/33
X=1.81 or if rounded 1.82

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So the z-scores that separate the unusual IQ scores from those that are usual are Z = -2 and Z = 2.

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Problems of normally distributed samples are solved using the z-score formula.

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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If Z<-2 or Z > 2, the IQ score is unusual.

So the z-scores that separate the unusual IQ scores from those that are usual are Z = -2 and Z = 2.

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Those IQ scores are X when Z = -2 and X when Z = 2. So

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