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jok3333 [9.3K]
3 years ago
13

Complete the following statement.

Mathematics
1 answer:
solong [7]3 years ago
7 0

Answer:

Hello dude

- 1 \frac{21}{24}  + 1 \frac{22}{24}  =  +  \frac{1}{24}

so it's positive

HAVE A NİCE DAY

Step-by-step explanation:

GREETİNGS FROM TURKEY ツ

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Simplify. Use a horizontal format. <br><br> (-2y2 - 4y - 11) + (4y2 - 4y)
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-4y-11 that the answer hope it helps
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A convex polyhedron has 10 faces and 11 vertices.<br><br> How many edges does it have?
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The <span>polyhedron has 12 faces

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The graph of f ′ (x), the derivative of f(x), is continuous for all x and consists of five line segments as shown below. Given f
Nataliya [291]

The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.

Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.

By the fundamental theorem of calculus,

\displaystyle f(5) = f(0) + \int_0^5 f'(x) \, dx

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so

\displaystyle \int_0^5 f'(x) \, dx = \frac{5+2}2 \times 2 = 7

\implies \max\{f(x) \mid 0\le x \le5\} = f(5) = f(0) + 7 = \boxed{13}

8 0
2 years ago
50 points take it or leave it<br> 3x+4=22
Lerok [7]

Answer:

<h2>X=6</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • equation
  • PEMDAS
<h3>let's solve:</h3>
  1. \sf cancel \: 4 \: from \: both \: sides :  \\  \sf   \implies \: 3x + 4 - 4 = 22 - 4 \\  \implies \sf \: 3x = 18
  2. \sf divide \: both \: sides \: by \: 3 :  \\  \sf  \bcancel \frac{3x}{3}  =  \frac{  \cancel{18} \:  \:  ^{6} }{ \cancel{ \: 3}}  \\  \therefore \rm \: x = 6

3 0
3 years ago
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Find the values of sin2u, cos2u, and tan2u given the figure.
Vadim26 [7]

Givens

y = 2

x = 1

z(the hypotenuse) = √(2^2 + 1^2)  = √5

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Sin(u) = y value / hypotenuse = 2/√5

Solve for sin2u

Sin(2u) = 2*sin(u)*cos(u)

Sin(2u) = 2(\dfrac{1}{\dsqrt{5}} * \frac{2}{\dsqrt{5}} = \dfrac{2}{5}) = 4/5

Solve for cos(2u)

cos(2u) = - sqrt(1 - sin^2(2u))

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Solve for Tan(2u)

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Notes

One: Notice that you would normally rationalize the denominator, but you don't have to in this case.  The formulas are such that they perform the rationalizations themselves.

Two: Notice the sign on the cos(2u). The sin is plus even though the angle (2u) is in the second quadrant. The cos is different. It is about 126 degrees which would make it a negative root (9/25)

Three: If you are uncomfortable with the  tan, you could do fractions.

\text{tan(2u)} = \dfrac{\dfrac{4}{5}}{\dfrac{-3}{5} } =\dfrac{4}{5} *\dfrac{5}{-3} =\dfrac{4}{-3}

7 0
3 years ago
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