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lakkis [162]
3 years ago
9

Please help!! 50 points!!

Mathematics
2 answers:
slava [35]3 years ago
7 0

Answer:

a. (5,-8)

b. 13 by 7

c. yes, the perimeter is 40 so 45 will do it!

S_A_V [24]3 years ago
3 0

Answer:

Step-by-step explanation:

A) 5,-8

B) 7 by 13

C)  40 and yes because 13+13+7+7=40

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Jennifer earns $7.60 per hour working after school. She wants to buy a musical instrument and she needs at least $500. Write an
slega [8]

Answer:

Step-by-step explanation:

let h be the number of hours.

7.60 h≥ 500

76h≥5000

6 0
3 years ago
Which relation is a function of x? A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 2, 2, 3. Column
Trava [24]

Answer:

  Column 1 is labeled x with entries negative 3, negative 2, 4, 7. Column 2 is labeled y with entries negative 1, 5, 0, negative 1

Step-by-step explanation:

When a value is repeated for an x-entry, the relation is not a function. The last choice describes a table with unique x values.

8 0
3 years ago
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a cake divided into 10 equal slices.kim ate 3/5 of 1/2 of cake. what part of the whole cake did kim ate? ​
joja [24]

Answer:

3/10 of the whole cake

Step-by-step explanation:

When you divide a cake in halve you get 5 pieces on each side, if Kim ate 3/5 of 1/2 of the cake, then she ate 3 pieces, so she ate 3/10 of the cake, and other way to figure this out is multiplying the two fractions, 3/5 x 1/2 = 3/10

8 0
3 years ago
Find the equation of the cosine graphed.
Lunna [17]

Answer:

C) y = -cos(x) +2

Step-by-step explanation:

The centerline is 2, so 2 is added. That leaves out choices A and B.

There is a minimum (not a maximum) at x=0, so the multiplier is negative, eliminating choice D.

The correct equation is that of C: y = -cos(x) +2.

7 0
3 years ago
Determine whether the relation shown is a function. Explain how you know.
lutik1710 [3]

Answer:

  It is not a function

Step-by-step explanation:

The plot shows (1, 1) and (1, 3) are both defined by the relation. It does not pass the "vertical line test", which requires the relation be single-valued everywhere.

3 0
3 years ago
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