Please help!! 50 points!!
2 answers:
You might be interested in
The required equation is :
Now, let's find the required values :
period (p) = 6
[distance between any successive Crest or trough]
a = - 4 (flipped)
b = 2π/p = 2π/6 = π/3
k = -2
Distance of starting position from origin = k
Now, plug in the values ~
How far did the frog jump? the answer is one of the solutions of the quadratic equation
because that's where the frogs height is 0 (y=0) feet.
Use your favorite formula for quadratic equations. I got two solutions: 0 and 30. 0 is clearly the starting point and 30 feet is point where the frog lands.
The height is the maximum of the quadratic form. Use the formula for maximum x of a quadratic: xmax = -b/(2a) = -0.51/(2*0.017) = 15. The maximum at that point is ymax = 3.825
So, the correct answer is (a) 30 ft far and 3.83 high.
