An event manager recorded the number of people in different age groups that attended a music concert. Which data table accuratel
y represents the data in the histogram?
Help if you can, thank you.
Help if you can, thank you.
2 answers:
Answer:
Step-by-step explanation:
Great question, it is always good to ask away and get rid of any doubts that you may be having.
The Histogram shows the number of people on the right while the bottom shows the age range. To read the histogram you look at the tip of the gray bar on a certain age range and follow that to the right of the histogram to know how many people of that age range attended the music concert. Based on the histogram we can see that,
20 people aged 18-24 attended.
100 people aged 25-31 attended.
60 people aged 32-38 attended.
40 people aged 39-45 attended.
This means that the Data table that accurately represents the data in the histogram is the one that I have attached separately at the bottom.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
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Answer:
- -108.26
- -108.13
- -108.052
- -108.026
- -108
Step-by-step explanation:
A graphing calculator or spreadsheet is useful for making the repeated function evaluations required.
The average velocity on the interval [a,b] will be ...
v avg = (y(b) - y(a))/(b-a)
Here, all the intervals start at a=3, so the average velocity for the given values of t will be ...
v avg = (y(3+t) -y(3))/((3+t) -3) = (y(3+t) -y(3))/t
This can be computed for each of the t-values given. The results are shown in the attached table.
__
We note that the fractional part of the velocity gets smaller in proportion to t getting smaller. We expect it to go to 0 when t goes to 0.
The estimated instantaneous velocity is -108 ft/s.
_____
We can simplify the average velocity equation to ...
v avg = ((48(3+t) -26(t+3)^2) -(48(t+3) -26(3)^2)) / t
= (48t -26(t^2 +6t))/t
= 48 -26t -156
<em> v avg = -108 -26t</em>
Then the average velocity at t=0 is -108.
