Question

Suppose a life insurance policy costs $24 for the first unit of coverage and then $6 for each additional unit of coverage. Let C(x) be the cost for insurance of x units of coverage. What will 10 units of coverage cost?

Answer 1

Answer:

10 Units would cost $78

Step-by-step explanation:

We will be using the following equation to solve this problem

$C(x) = 24+6(x-1)$

Where x will be the amount of units of coverage that are sold. The equation subtracts 1 from the amount of units sold (since the first unit costs $24) and multiplies that by $6 which is the cost per unit. Then it adds $24 to that, which gives us the total cost.

Since we sold 10 units of coverage we plug that into the equation

$C(10) = 24+6(10-1)$

$C(10) = 24+6(9)$

$C(10) = 24+54$

$C(10) = 78$

So 10 units of coverage sold would cost $78

Answer 2

Answer:

C(x) =24+6(z-1) where z is the total of units sold.

Therefore if z=10 units, the answer is: C(x)=24+6(10-1)

Or 24+6(9)

Or $78

Step-by-step explanation: