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Juliette [100K]
3 years ago
10

How many solutions are there to this system? A. None B. Exactly 1 C. Exactly 2 D. Exactly 3 E. Infinitely many F. None of the ab

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Mathematics
1 answer:
Valentin [98]3 years ago
4 0

Hello, you haven't provided the system of equations, therefore I will show you how to do it for a particular system and you can follow the same procedure for yours.

Answer:

For E1 -> Exactly one

For E2 -> None

For E3 -> Infinitely many

Step-by-step explanation:

Consider the system of equations E1:  y = -6x + 8 and 3x + y = 4, replacing equation one in two 3x -6x +8 = 4, solving x = 4/3 and replacing x in equation one y = 0. This system of equations have just one solution -> (4/3, 0)

Consider the system of equations E2:  y = -3x + 9 and y = -3x -7, replacing equation one in two -3x + 9 = -3x -7, solving 9 = -3. This system of equations have no solution because the result is a fallacy.

Consider the system of equations E3:  2 = -6x + 4y and -1 = -3x -2y, taking equation one and solving y = 1/2 + 3/2x, replacing equation one in two -1 = -3x -1 +3x, solving -1 = -1. This system of equations have infinitely many solution because we find a true equation when solving .

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Factorise:2x^4+x^3-14x^2-19x-6
tester [92]

Answer:

(x+1)(2x+1)(x+2)(x−3)

Step-by-step explanation:

Factor 2x^4+x^3−14x^2−19x^−6

2x^4+x^3−14x^2−19x^−6

=(x+1)(2x+1)(x+2)(x−3)

6 0
3 years ago
I have a question about polynomial division it is in the picture
Cloud [144]

To answer this question, we have to do the long division process for polynomials. We can do the operation as follows:

To do this division process, we have:

1. Divide the first term of the dividend by the first element of the divisor. They are:

\frac{-4x^3}{4x^2}=-x

2. Now, we have to multiply this result by the divisor, and the result will change its sign since we have to subtract that result from the dividend as follows:

-x\cdot(4x^2_{}-4x-4)=-4x^3+4x^2+4x

And since we to subtract this result from the dividend, we end up with:

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3. Then we have the following algebraic addition:

\frac{\begin{cases}-4x^3+24x^2-15x-15 \\ 4x^3-4x^2-4x\end{cases}}{20x^2-19x-15}

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5. And we have to multiply 5 by the divisor, and the result will be subtracted from the dividend:

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Since we have to subtract this from the dividend, we have:

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6. And we have to add this algebraically to the dividend we got in the previous step:

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And this is the remainder of the division, x + 5.

As we can see from the division process, we got as:

1. The quotient: -x + 5

q=-x+5

2. The remainder: x + 5.

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Since we have that the dividend = divisor * quotient + remainder.

Therefore, the result for this division is:

-4x^3+24x^2-15x-15=(4x^2-4x-4)\cdot(-x+5)+(x+5)

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