I'm not exactly sure of what you mean, but if the number (for example) were 2,3, and 6 you could say 2 and 6 multiply to get 6 and 6 divided by 2 would be 3 and so on. You could do this with any operation. Hope this helps, and sorry if this wasa little unclear.
An arithmetic sequence takes the form

where

is the common difference between terms. You can solve for

in terms of any of the previous terms of the sequence:

for some integer

Continuing in this way, you know that the sequence can be defined explicitly in terms of the first term


Given that the 4th term is

and the 11th term is

, you have the following system of equations.

Solving this system for the two unknowns yields

and

.
So, the sequence is given explicitly by
Answer:
96:180:204 inches
Step-by-step explanation:


<em><u>Solution:</u></em>
<em><u>We have to find the inequalities that are true</u></em>
<em><u>Option 1</u></em>

0.6 is not less than 0
Thus this inequality is not true
<em><u>Option 2</u></em>

0.667 is greater than 0.5
Thus this inequality is true
<em><u>Option 3</u></em>

0.818 is less than 1
Thus this inequality is true
<em><u>Option 4</u></em>

0.5 = 0.5
Thus the above inequality is not true
Answer:
108, 108, 72
Step-by-step explanation:
Vertical angles are congruent and if the measure of 1 of the angles is 72 degrees and straight lines equal 180 degrees you have to subtract 72 from 180 which equals 108.