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gogolik [260]
4 years ago
15

PLEASE HELP!!!! A department store's customer parking lot has 4 rows with an equal number of parking spots in each row. The lot

also has 15 parking spots for store employees. If c cars can be parked in each of the 4 main rows of the parking lot, what is the expression for the maximum number of cars that can be parked in the parking lot?
a.15c − 4
b.c(15 − 4)
c.4c + 15
d.4(c + 15)
Mathematics
1 answer:
Monica [59]4 years ago
5 0
C cars can be parked in each rows. so total cars in 4 rows = 4 x c = 4c

including 4c, 15 additional cars can be parked. so, maximum cars that can be parked = 4c + 5.

the answer is c
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SVETLANKA909090 [29]
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Divide both sides by 5 to get x.
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2) Again, we can set up a proportion to solve for x because we know the lines are parallel. 24/36=x/12. 24/36 simplifies to 2/3 so 2/3=x/12. Cross multiply to get this: 3x = 24. Divide both sides by 3 to get x.
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3 0
4 years ago
Use the parabola tool to graph the quadratic function f(x)=−5x2−2.
alexira [117]

\text{Consider the quadratic function}\\
\\
f(x)=-5x^2-2\\
\\
\text{For a quadratic equation, }f(x)=ax^2+bx+c, \text{ we know that the x-coordinate}\\
\text{of the vertex (h,k) is given by}\\
\\
h=\frac{-b}{2a}\\
\\
\text{on comparing the given equation with standard equation, we have}

a=-5, b=0, c=-2\\
\\
\text{so the x-coordinate of the vertex is }\\
\\
h=-\frac{b}{2a}=-\frac{0}{2(-5)}=0\\
\\
\text{so plug this vlaue of the h in the given function to get the y-coordinate}\\
\text{of the vertex. so}\\
\\
f(x)=-5(0)^2-2=0-2=-2\\
\\
\text{hence the vertex of the parabola is: }(h,k)=(0,\ -2)\\
\\
\text{A second point on the graph can be found by putting x=1, so }\\
\\
f(1)=-5(1)^2-2=-5-2=-7\\
\\
\text{so one other point on the parabola is }(1,-7)

The grpah of the quadratic function is shown below:


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Gemiola [76]

Answer:

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Step-by-step explanation:

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