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BlackZzzverrR [31]
3 years ago
7

Find the minimum and maximum values of the objective function z=3x+5y

Mathematics
2 answers:
Margarita [4]3 years ago
6 0
3.15 addd all of them! Then divide
kakasveta [241]3 years ago
3 0

The answer to the question is

3.15

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For a polynomial p(x), the value of p(3) is −2. Which of the following must be true about p(x)?
mr Goodwill [35]

Answer:

D

Step-by-step explanation:

The factor theorem states if (x - h) is a factor of a polynomial p(x) then

p(h) = 0

However, p(h) ≠ 0 then the value obtained is the remainder.

Thus

p(3) = - 2

When p(x) is divided by (x - 3) then the remainder is - 2

8 0
3 years ago
Georgie signed up for a new streaming service. It costs him $13.99 for the
Kamila [148]

Answer:

y= 3.99x + 13.99

Step-by-step explanation:

slope intercept is y= mx + b. X is going to be a factor thats going to be multiplied (per month), and in addition to that will be the 13.99 as basically the starting fee.

5 0
4 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulbs. The
Bond [772]

Answer:

34% of lightbulb replacement requests numbering between 47 and 52

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 52

Standard deviation = 5

Between 47 and 52:

52 is the mean and 47 is one standard deviation below the mean.

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean.

Since the normal distribution is symmetric, of those, 34% are within 1 standard deviation below the mean and the mean(47 and 52) and 34% are within the mean and one standard deviation above the mean(52 and 57).

So

34% of lightbulb replacement requests numbering between 47 and 52

3 0
3 years ago
Whats the lowest common multiple of 120 and 19600​
Levart [38]

Answer:

Multiples of 120 are 120, 240, 360, 480, 600, 720, 840 etc; Multiples of 150 are 150, 300, 450, 600, 750, 900 etc; Therefore, the least common multiple of 120 and 150 is 600.

Least common multiple (LCM) of 19600 and 19619 is 384532400.

4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B20%7D%7B16%7D%20%2A%20100" id="TexFormula1" title=" \frac{20}{16} * 100" alt=" \f
mart [117]
125% because sixteen is equal to a whole which is equal to one-hundered and one fourth of sixteen is four and sixteen plus four is twenty. one fourth of one-hundered is twenty-five so you add the twenty-five to the one-hundered and you get 125%
8 0
3 years ago
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