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3 years ago

Help with this math question

Mathematics

1 answer:

Yakvenalex [24]3 years ago

6 0

Garden Eel-396 > Great White Shark -430 > Sea Urchin -452 > Sea Turtle -502

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Yan has already finished 3/5 of the 45 math problems he was assigned today. Each math problem took him 1 4/5 of a minute to comp

kobusy [5.1K]

Answer:

He will finish the rest of the problems in 32.4 minutes.

Step-by-step explanation:

Since we are given that Yan has completed 3/5 of 45 problems i.e.

$\frac{3}{5}*45$

$27$

Thus he has completed 27 problems

Remaining no. of problems are 45-27 = 18

Since he complete each problem in minutes = $1\frac{4}{5} =\frac{9}{5} =1.8$

So, he completes 18 problems in minutes = 18 *1.8 = 32.4 minutes

Hence , He will finish the rest of the problems in 32.4 minutes.

3 0

3 years ago

In Triangle XYZ, measure of angle X = 49° , XY = 18°, and

marissa [1.9K]

Answer:

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

$YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X$ (1)

If we know that $X = 49^{\circ}$ , $XY = 18$ and $YZ = 14$ , then we have the following second order polynomial:

$14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}$

$XZ^{2}-23.618\cdot XZ +128 = 0$ (2)

By the Quadratic Formula we have the following result:

$XZ \approx 15.193\,\lor\,XZ \approx 8.424$

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

$XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y$

$\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}$

$Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)$

1) $XZ \approx 15.193$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 54.987^{\circ}$

2) $XZ \approx 8.424$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 27.008^{\circ}$

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

6 0

3 years ago

The black triangles are similar. Find the value of x. No links please!!

igor_vitrenko [27]

9514 1404 393

Answer:

Step-by-step explanation:

The altitude of the triangle is 12/21 = 4/7 of the marked side. If we assume that the marked sides are the ones that are corresponding, then ...

x = (4/7)(28)

x = 16

8 0

3 years ago

(01.03 MC) Which of the following is a step in simplifying the expression (Xy^4/x^-5y^5)^3

Sati [7]

$\displaystyle\tt\left(\frac{xy^4}{x^{-5}y^5}\right)^{-3} =\frac{x^{-3}y^{4\cdot(-3)}}{x^{-5\cdot(-3)}y^{5\cdot(-3)}}=\boxed{\tt\frac{x^{-3}y^{-12}}{x^{15}y^{-15}}}$

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3 years ago

A rectangle has an area of 96 in2. The rectangle's base is 4 in. What is the height of the rectangle?

gavmur [86]

96/4=24in, so B
Hope this helps :)

6 0

3 years ago

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