The ordered pair which makes both inequalities true is: D. (3, 0).
<h3>How to determine ordered pair?</h3>
In Mathematics, an inequality can be used to show the relationship between two (2) or more integers and variables in an equation.
In order to determine ordered pair which makes both inequalities true, we would substitute the points into the inequalities as follows:
At (0, 0), we have:
y > -2x + 3
0 > -2(0) + 3
0 > 3 (false).
y < x – 2
0 < 0 - 2
0 < -2 (false)
At (0, -1), we have:
y > -2x + 3
-1 > -2(0) + 3
-1 > 3 (false).
y < x – 2
-1 < 0 - 2
-1 < -2 (false)
At (1, 1), we have:
y > -2x + 3
1 > -2(1) + 3
1 > -1 (true).
y < x – 2
1 < 1 - 2
1 < -1 (false)
At (3, 0), we have:
y > -2x + 3
0 > -2(3) + 3
0 > -3 (true).
y < x – 2
0 < 3 - 2
0 < 1 (true).
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(n+1)x 2=10
2n+2=10
2n=8
n=4
The - number has to t o be more then 6 in order to get -10. Answer= -16
Last choice 1 9/50
118/100 =
(2 × 59)/(22 × 52) =
((2 × 59) ÷ 2) / ((22 × 52) ÷ 2) =
59/(2 × 52) =
59/50
Then
59 ÷ 50 = 1 and remainder = 9 =>
59 = 1 × 50 + 9 =>
59/50 =
(1 × 50 + 9) / 50 =
1 + 9/50 =
1 9/50
Answer:
y = 
Step-by-step explanation:
Given y varies directly with x then the equation relating them is
y = kx ← k is the constant of variation
To find k use the condition y = - 8 when x = 20
k = 
= 
= - 
y = - x ← equation of variation
When x = - 4, then
y = - × - 4 =
