Can someone help please

Mathematics

2 answers:

icang [17]3 years ago

8 0

I would say C because you multiply 3 x H then 3 x4 I think this is the right answer but I'm not so sure though Hope it helped sort of - Ashlynn

Brums [2.3K]3 years ago

6 0

I would also say C.
3*4=12
thats all i did :)

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MariettaO [177]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's find out the gradient (Slope " m ") of line q ;

$\qquad \sf \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\qquad \sf \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}$

$\qquad \sf \dashrightarrow \:m = - 4$

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

$\qquad \sf \dashrightarrow \:y - 4 = m(x - 0)$

$\qquad \sf \dashrightarrow \:y = mx + 4$

Now, plug in the value of gradient ~

$\qquad \sf \dashrightarrow \:y = - 4x + 4$

here we can clearly observe that, the Area under the curve can easily be represented as :

$\qquad \sf \dashrightarrow \:y < - 4x + 4$

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

5 0

2 years ago

What are the solutions to this equation?

ziro4ka [17]

$\displaystyle\\(x-4)^2=49\\\\(x-4)^2-49=0\\\\(x-4)^2-7^2=0\\\\(x-4-7)(x-4+7)=0\\\\(x-11)(x+3)=0\\\\x-11 = 0~~~\text{or}~~~x+3=0\\\\x-11=0~~~\implies~~~\boxed{x_1=11}\\\\x+3=0~~~\implies~~~\boxed{x_2=-3}\\\\\boxed{\bf The~solutions~are:~~x =11~~\text{or}~~x =-3}$