Is the equation like this? x^2 + 25y^2?
If the equation is like that, the answer would be (x-5y)^2 or (x-5y)(x-5y).
how did I get this? Just divide the factors or the get the square root of 25y^2 and it would be 5y. Then just try if it is positive or negative. In this case, it is negative because there is no factor w/ no exponential form. I hopemy answer helped you.
Answer:
The correct answer to your question is A because your asking for the vertex of the equation.
Step-by-step explanation:
Vertex Algebraic Equations
Answer:
The equation of the line would be y = 1/5x + 6
Step-by-step explanation:
First, to find the slope of a perpendicular line, you need to find the opposite and reciprocal of the original slope. Since the original is -5, we first change the sign (which makes it just 5). Now we take that 5 and flip it to get 1/5.
Now that we have the slope as 1/5, we can use that and the intercept in slope-intercept form to get the equation.
y = mx + b
y = 1/5x + 6
Answer:
] y=x-4
-2x+y=18
y - x = -4
y - 2x = 18
equation [2] for the variable y
[2] y = 2x + 18
// Plug this in for variable y in equation [1]
[1] (2x+18) - x = -4
[1] x = -22
// Solve equation [1] for the variable x
[1] x = - 22
// By now we know this much :
y = 2x+18
x = -22
// Use the x value to solve for y
y = 2(-22)+18 = -26
Step-by-step explanation:
please mark me as brainlist please
<em>Answer:</em>
25.4639073013
Rounded is 25.4
<em>Have a beautiful day! </em>v(⌒o⌒)v♪
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