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Black_prince [1.1K]
3 years ago
8

What is the range of the function (e^x)/(e^x)+c? Assume that c is a constant greater than zero.

Mathematics
1 answer:
mr_godi [17]3 years ago
4 0
Try this explanation:
1. if to re-write the given function as:
y= \frac{e^x}{e^x+C}; \ \ \textless \ =\ \textgreater \  \ y=1- \frac{C}{e^x+C};
then it is possible to define its range:
2)   
\lim_{x \to+ \infty}[1- \frac{C}{e^x+C}]=1;  \\ \lim_{x \to- \infty}[1- \frac{C}{e^x+C}]=0

answer: (0;1)
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<h2>3.112<em> </em><em>because</em><em> </em><em>5</em><em>6</em><em>+</em><em>5</em><em>6</em><em>=</em><em>1</em><em>1</em><em>2</em></h2>
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translates to:

8(x) + 5(y) = -13

The sum of (the number) and (the other number) is 1.

translates to:

(x) + (y) = 1


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\rm 8x+5y=-13\\&#10;~~x+~~y=~~~~1

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We'll multiply the second equation by -8 so that the x's match up.

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When we add the equations together, the x's will fall out of the equation, summing to zero. The 5y and -8y will sum to -3y and the right hand side will sum to -21.

\rm -3y=-21

Divide by -3,

\rm y=7

Plug back into one of your original equations to find the value of x,

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Subtract 7,

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