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musickatia [10]
2 years ago
15

Identify the parent function and describe the transformation of f(x)=3^x+5​

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
7 0

Answer:

count it and identify it

the answer is 4

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FromTheMoon [43]
Hope this helped you :)

4 0
3 years ago
Use a trigonometric ratio to find the value of x. Round your answer to the nearest<br> tenth.
belka [17]

Answer:

x=63.256%   63.3-rounded to the nearest tenth.

Step-by-step explanation:

8 0
3 years ago
How did astronomer Yi Xing (A.D. 683-727) contribute to the development of mathematics in china?
SSSSS [86.1K]

Answer:

Yi Xing invented the astronomical clock and introduced some new methods of interpolation in mathematics.

Step-by-step explanation:

Yi Xing was both an astronomer and a mathematician during the era. He invented the astronomical clock which was more accurate than the initial water and Sun's clock in use.

Furthermore, Yi Xing also discovered some new methods of interpolation in mathematics of which the meaning and interpretation became controversial. Interpolation is a method majorly in mathematics that can be used to estimate a value of a function from its discrete values. It involves first order differences and second order differences.

Also, Yi Xing was able to design a calendar in A.D. 727.

4 0
3 years ago
What is the period of the graph of y = 5 sin (pi x) + 3?
Natasha2012 [34]

Equate whats inside (arguments) \sin with base period of sine function 2\pi and solve for x to get period,

\pi x=2\pi\implies x=2

So the period of the graph of the given function is precisely 2.

Hope this helps :)

7 0
3 years ago
Find the difference between8/15 and 2/3 Show all calculations in your final answer.
kherson [118]

Answer:

  • \frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}          

Step-by-step explanation:

  • Let the value of a number 'a' be = 8/15
  • Let the value of a number 'b' be = 2/3

The difference between the two numbers can be calculated by subtracting the numbers

a-b=\frac{8}{15}-\left(\frac{-2}{3}\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

         =\frac{8}{15}-\frac{-2}{3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

          =\frac{8}{15}-\left(-\frac{2}{3}\right)

\mathrm{Apply\:rule}\:-\left(-a\right)=a

          =\frac{8}{15}+\frac{2}{3}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

          =\frac{8+10}{15}

          =\frac{18}{15}

\mathrm{Cancel\:the\:common\:factor:}\:3

           =\frac{6}{5}

Thus,

  • \frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}                    
3 0
2 years ago
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