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3 years ago

How do you evaluate a function?

1 answer:

8 0

Substitute the input (the given number or expression) for the function's variable (place holder, x). Replace the x with the number or expression. Given thefunction f (x) = 3x - 5, find f (4). Solution: Substitute 4 into the functionin place of x.

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Find the area of the trapezoid shown. A. 39 square root 3 sq units B. 43.5 sq units C. 43.5 square root 3 sq units

Ivan

Answer:

43.5√3 sq. units

Step-by-step explanation:

Base 1 of trapezoid is 10.

Base 2 of trapezoid is 16 + 3 = 19

The height = 3√3 (To get the height you had to multiply the number 3 from the bottom base of the trapezoid by the square root of three)

Now plug these numbers into the trapezoid formula: A = 1/2(3√3)(10 + 19)

Simplify to get: 43.5√3 sq. units

Hope this helps you understand! P.S. I helped someone else out on this problem, so I just copied and pasted my answer from the previous brainly question onto here. :) So, it's still my own work.

5 0

3 years ago

Is the following a rational or irrational number:<br><br> 0.7077077707777…

HACTEHA [7]

Answer:it following number is irrational

Step-by-step explanation:

8 0

3 years ago

Write an equation of the line that passes through the given point and is perpendicular to the given line.

topjm [15]

Answer:

y = - 3x - 22

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{1}{3}$ x + 1 ← is in slope- intercept form

with slope m = $\frac{1}{3}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{1}{3} }$ = - 3 , then

y = - 3x + c ← is the partial equation

To find c substitute (- 6, - 4) into the partial equation

- 4 = 18 + c ⇒ c = - 4 - 18 = - 22

y = - 3x - 22 ← equation of perpendicular line

6 0

3 years ago

Find the x- and y-intercepts of the graph of the linear equation 2x − 3y = −10

aivan3 [116]

Answer:

-5 is the x and 10/3 is the y i think

Step-by-step explanation:

7 0

3 years ago

Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin

ozzi

$I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt$

by using the integration formula

we get,

$\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c$

now put the value of t=\sin\theta in the above equation

we get,

$\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c$

hence proved

7 0

3 years ago