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2 answers:
Question 1 is correct. AM = 4 and CM cong. AM therefore CM = 4.
Question 2 is correct. Triangles congruent by SAS --> BA cong BC = 12
Question 3 Line BM intersects point D
Questions 4-6 Attachement 1 is an example with these triangles and their circumcenters as det. by their perp. bisectors. As you can see:
The POC of a right triangle lies on the triangle, acute, inside, and obtuse, outside.
Question 7-8 First off: DF = 6, not BD.
We can clearly see 6 congruent triangles within this equilateral one.
BD corresponds to AD and = 11.5
So does DC.
Question 9-10 See attachement 2
Question 11 Sometimes -- see the right triangle in attachment 1
Question 12 Never -- See attachment 4, of course you can always just draw one for yourself. Just draw an acute, right, and obtuse triangle!
Question 13 Always -- See attahcment 3
Question 14 Never -- See attachment 3
Question 15 Sometimes -- see obtuse triangle in attachment 1
Question 2 is correct. Triangles congruent by SAS --> BA cong BC = 12
Question 3 Line BM intersects point D
Questions 4-6 Attachement 1 is an example with these triangles and their circumcenters as det. by their perp. bisectors. As you can see:
The POC of a right triangle lies on the triangle, acute, inside, and obtuse, outside.
Question 7-8 First off: DF = 6, not BD.
We can clearly see 6 congruent triangles within this equilateral one.
BD corresponds to AD and = 11.5
So does DC.
Question 9-10 See attachement 2
Question 11 Sometimes -- see the right triangle in attachment 1
Question 12 Never -- See attachment 4, of course you can always just draw one for yourself. Just draw an acute, right, and obtuse triangle!
Question 13 Always -- See attahcment 3
Question 14 Never -- See attachment 3
Question 15 Sometimes -- see obtuse triangle in attachment 1
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so... the 0.75 or 3/4 is our "multiplier" to get the next term's value, or our "common ratio". So is just a geometric sequence, if the first term is 30, the common ratio is 0.75, what's the 4th term? Because the first bounce happens after the 30 feet, at the 2nd term, thus the 4th term is the 3rd bounce.
so... the 0.75 or 3/4 is our "multiplier" to get the next term's value, or our "common ratio". So is just a geometric sequence, if the first term is 30, the common ratio is 0.75, what's the 4th term? Because the first bounce happens after the 30 feet, at the 2nd term, thus the 4th term is the 3rd bounce.
3(4x+2) - 6x = 5x - 5(2 + x)
3·4x+3·2-6x=5x-5·2-5·x
12x+6-6x=5x-10-5x
12x-6x-5x+5x= -10-6
6x=-16
3·4x+3·2-6x=5x-5·2-5·x
12x+6-6x=5x-10-5x
12x-6x-5x+5x= -10-6
6x=-16