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Tanya [424]
3 years ago
10

The mass of 5m^3 of copper is 44800kg. Work out the density of copper.

Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0
Okay so

Density= mass/volume

44800 kg/5m^3 = 8960kg/m^3
which units are preferred?

1000g/kg
1000000 cm ^3/ m^3
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So I don't understand how V = lwh (h).... the topic is literal equations.
Kruka [31]

1) Solving in terms of h

V = lwh <em>Divide both sides by h</em>

<em />

\begin{gathered} V\text{ = lwh} \\ \frac{V}{h}=\frac{lwh}{h} \\ \frac{V}{h}\text{ =}lw\text{ Cross multiply} \\ hlw=V\text{ Divide both sides by lw} \\ \frac{hlw}{lw}=\text{ }\frac{V}{lw} \\ h\text{ = }\frac{V}{lw} \end{gathered}

So rearranging that equation we can find h, in terms of V, and l and w.

If we want to solve in terms of l, or w, we'll proceed similarly to isolate the variable we want on the left side, and the other terms on the right side.

6 0
1 year ago
A sum of money is divided into the ratio 3:4. The larger portion is then divided into 3 parts in
vivado [14]

Step-by-step explanation:

this is your answer.........

5 0
3 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
3 years ago
Absolute value inequality<br>4 |x+7| divided by 3. ?
stira [4]

Answer:

4 |x+7| divided by 3.

Step-by-step explanation:

This cannot be divided any further.

3 0
3 years ago
In a randomly selected sample of 1169 men ages 35–44, the mean total cholesterol level was 210 milligrams per deciliter with a s
Aneli [31]

Answer:

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 210, \sigma = 38.6

Find the highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10%.

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 210}{38.6}

X - 210 = -1.28*38.6

X = 160.59

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

5 0
3 years ago
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