Answer:
440hz
Explanation:
saxophone a plays at 430hz and a frequency of 5 beats per second can be heard so saxophone b is playing at a frequency 10hz louder than saxophone A making it 440hz
Here we have to calculate the acceleration of the wagon.
as per the question the mass of the wagon is given as 20 kg
the horizontal force that is applied on the body is 64 newton.
as the perfect unit of the fore is not mentioned it may be 64N or 64 dyne or 64 kgf.
as per Newton's second law of motion we know that the rate of change of momentum is the applied force.from the quantitative definition of Newton's second law we know that applied force is equal to the product of mass and acceleration.
hence
let F= 64 N,then
a=3.2 m/s^2
if F=64kgf=64×9.8 N,then
=31.36 m/s^2
if F =64 dyne ,the acceleration is found to be 0.0032 cm/s^2 [ans]
Answer:
<h2>64.4 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 9.2 kg
acceleration = 7 m/s²
We have
force = 9.2 × 7 = 64.4
We have the final answer as
<h3>64.4 N</h3>
Hope this helps you
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The ball's weight is mathematically given as
m=2.44*10^30
<h3>What is the ball's weight?</h3>
Question Parameters:
Q=1.6*10^{10}
E=15.0*10^{20}
Generally, the equation for the mass is mathematically given as
m=EQ/g
Therefore
m=1.6*10^{10}*15.0*10^{20}/9.81
m=2.44*10^30
In conclusion
The weight of the ball is
m=2.44*10^30
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