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Irina-Kira [14]
3 years ago
5

. A grindstone increases in angular speed from 4.00 rad/s to 12.00 rad/s in 4.00 s. Through what angle does it turn during that

time if the angular acceleration is constant?
Physics
1 answer:
ZanzabumX [31]3 years ago
5 0

Answer:

\theta=32rad

Explanation:

In an uniformly accelerated circular motion, the angle traveled by the object is given by:

\theta=\frac{\omega_f+\omega_0}{2}t

Here \omega_f is the final angular speed, \omega_0 is the initial angular speed and t is the time of the motion. Replacing the given values:

\theta=\frac{12\frac{rad}{s}+4\frac{rad}{s}}{2}(4s)\\\theta=32rad

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