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yanalaym [24]
3 years ago
7

The rate constant for this second‑order reaction is 0.760 M−1⋅s−1 at 300 ∘C. A⟶products How long, in seconds, would it take for

the concentration of A to decrease from 0.750 M to 0.330 M?
Physics
1 answer:
Mashcka [7]3 years ago
3 0

Answer:

2.23 s

Explanation:

For a second-order reaction:

1 / [A] = 1 / [A]₀ + kt

Given [A] = 0.330 M, [A]₀ = 0.750 M, and k = 0.760 M⁻¹s⁻¹:

1 / 0.330 = 1 / 0.750 + 0.760t

t = 2.23

It would take 2.23 seconds.

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Since temperature increases when the average kinetic energy of particles increases, what is happening to the added energy when t
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Latent heat is the heat required to change the phase. When the temperature remains constant during melting or boiling the added energy is employed in the phase change process.

<h3>What is average kinetic energy?</h3>

The average kinetic energy (KE) is defined as the one-half of the mass of each gas molecule times multiplied by the square of RMS velocity.

KE = \frac{1}{2}m (V_{rms})^{2}

where,

KE is the kinetic energy

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(V)rms is the RMS velocity

As we know since the temperature is increasing the average kinetic energy of the particle increases. So the added energy is utilized in the sensible heat due to which the temperature of the body increases resulting in the increase in average kinetic energy

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6 0
2 years ago
on a recent adventure trip, Anita Break went rock climbing. Anita was able to perform 1370 J of work in 100 seconds. Determine A
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        Power = (energy) / (time)

         =    (1370 joules) / (100 seconds)

         =       13.7  joules/second

         =       13.7 watts .

That's not an awful lot of power, especially for a strenuous activity like
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Compare 13.7 watts to the light power coming out of a 20-watt night light.

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5 0
3 years ago
A 920-kg compact car moving at 92 m/s has approximately 3,893,440 Joules of kinetic energy. What is the change in kinetic energy
tensa zangetsu [6.8K]

Answer:

Change in kinetic energy = 3297280 J

Explanation:

Given that,

Mass, m = 920 kg

Speed of a car, v = 92 m/s

Kinetic energy, K = 3,893,440 J

If the speed of a car, V = 36 m/s

Net kinetic energy is given by :

K_n=\dfrac{1}{2}mV^2\\\\=\dfrac{1}{2}\times 920\times (36)^2\\\\K_n=596160\ J

The change in kinetic energy = 3,893,440 - 596160

= 3297280 J

So, the change in kinetic energy of the car is 3297280 J.

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