I’m so so so so sorry I don’t know
Latent heat is the heat required to change the phase. When the temperature remains constant during melting or boiling the added energy is employed in the phase change process.
<h3>What is average kinetic energy?</h3>
The average kinetic energy (KE) is defined as the one-half of the mass of each gas molecule times multiplied by the square of RMS velocity.

where,
KE is the kinetic energy
m is the mass of each molecule
(V)rms is the RMS velocity
As we know since the temperature is increasing the average kinetic energy of the particle increases. So the added energy is utilized in the sensible heat due to which the temperature of the body increases resulting in the increase in average kinetic energy
But when the temperature remains constant during melting or boiling the added energy is converted into latent heat energy utilized to convert the phase of a substance.
To learn more about the average kinetic energy refer to the link ;
brainly.com/question/24134093
Power = (energy) / (time)
= (1370 joules) / (100 seconds)
= 13.7 joules/second
= 13.7 watts .
That's not an awful lot of power, especially for a strenuous activity like
rock-climbing. Shoot ! Even I could probably perform at that level.
Compare 13.7 watts to the light power coming out of a 20-watt night light.
13.7 watts = 0.018 horsepower. (rounded)
Answer:
Change in kinetic energy = 3297280 J
Explanation:
Given that,
Mass, m = 920 kg
Speed of a car, v = 92 m/s
Kinetic energy, K = 3,893,440 J
If the speed of a car, V = 36 m/s
Net kinetic energy is given by :

The change in kinetic energy = 3,893,440 - 596160
= 3297280 J
So, the change in kinetic energy of the car is 3297280 J.
Direct current (DC) is the flow of electric charge in only one direction. It is the steady state of a constant-voltage circuit. Most well-known applications, however, use a time-varying voltage source. Alternating current (AC) is the flow of electric charge that periodically reverses direction.
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<em>#</em><em>L</em><em>E</em><em>T</em><em>S</em><em> </em><em>STUDY</em></h2>