Base on your diagram it is a Series-Parallel type of connections right? So based on my calculation and the rule in computing the resistance and voltage of a parallel and series. The total resistance is 1.25 and the total voltage is 2.04 V
The force of gravity increases with mass, but decreases with increasing distance between objects.
Answer:
2954.6 N/C, 46.36 degree from positive axis
Explanation:
E1 = 1300 N/C, θ1 = 35 degree
E2 = 1700 N/C, θ2 = 55 degree
Now write the electric fields in vector form
E1 = 1300 ( Cos 35 i + Sin 35 j) = 1064.9 i + 745.6 j
E2 = 1700 ( Cos 55 i + Sin 55 j) = 975.08 i + 1392.6 j
Resultant electric field
E = E1 + E2
E = 1064.9 i + 745.6 j + 975.08 i + 1392.6 j
E = 2039.08 i + 2138.2 j
Magnitude of E
E = sqrt (2039.08^2 + 2138.2^2)
E = 2954.6 N/C
Let it makes an angle Φ from X axis
tan Φ = 2138.2 / 2039.08 = 1.049
Φ = 46.36 degree from positive X axis.
The value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.
<h3>What is impedance Z of the circuit?</h3>
The impedance Z of the circuit is the ratio of voltage amplitude to the maximum current.

Here, <em>V </em>is voltage amplitude and<em> I</em> maximum current.
A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 490V. The rate at which electrical energy is dissipated in the resistor is 316 W.
The rate at which electrical energy is dissipated in the resistor is the product of the resistance and the square of current. Thus,

The impedance Z of the circuit is,

Thus, the value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.
Learn more about the impedance Z of the circuit here:
brainly.com/question/24225360
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270/70^2 = x/80^2
Cross multiply
270 (6400) = 4900x
x = 270(6400)/4900
352 and 32/49 feet
Hope this helps