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nalin [4]
3 years ago
5

Please help me with this!!!!

Mathematics
2 answers:
Ghella [55]3 years ago
7 0

Answer:

3, 6, 12, 24 , 48, 96


ad-work [718]3 years ago
3 0

Answer: the no. is doubled every time we get an answer. therefore the next two no.s n the sequence are 48, 96



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a cross section of a parabolic glass mirror of the Hubble space telescope shown can be modeled by the graph of the function y=0.
PilotLPTM [1.2K]

You need to divide this one :)


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8 0
3 years ago
Can you please help will give brainliest please
Brrunno [24]
The perimeter is 18. Which would be the distance.
4 0
3 years ago
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Dave is on a kayaking trip. On the first day, he travels 15 miles. On the second day, he travels 35 miles and the third day he r
zubka84 [21]

Answer:

30 miles

Step-by-step explanation:

average= sum of miles ÷ days to cover = 30

HOPE IT HELPS

5 0
3 years ago
A box is in the shape of an equilateral triangular prism. if the box is to be covered with paper on its lateral sides, how many
Zarrin [17]

The total surface area of the triangular prism that has a height of h and the side length of a is given below.

\rm a(\dfrac{\sqrt3}{2} \ a + 3h)

<h3>What is a triangular prism?</h3>

A triangular prism is a closed solid that has two parallel triangular bases connected by a rectangle surface.

A box is in the shape of an equilateral triangular prism.

If the box is to be covered with paper on its lateral sides.

Let a be the side length of the equilateral triangle and h be the height of the prism.

Then the surface area of the triangular prism will be

Surface area = 2 × area of triangle + 3 × area of the rectangle

The area of the triangle will be

\rm Area\ of\ triangle = \dfrac{\sqrt{3}a^2}{4}

The area of the rectangle will be

\rm Area \ of \ rectangle = a \ h

Then the total surface area will be

\rm Surface\ area =  2 \times \dfrac{\sqrt3 a^2 }{4} + 3 ah\\\\\\Surface\ area =  a(\dfrac{\sqrt3}{2} \ a + 3h)

More about the triangular prism link is given below.

brainly.com/question/21308574

7 0
2 years ago
A certain isotope decays so that the amount A remaining after t years is given by: A = A0 · e ^-0.03t where A0 is the original a
Katena32 [7]
<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k  (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187 </span>
about 23 years
</span></span>
7 0
3 years ago
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