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JulsSmile [24]
3 years ago
5

Which is true? A 10.59 > 10.60 B 10.590 = 10.59 C 10.43 < 10.24 D 9.0005 = 9.0050

Mathematics
2 answers:
Allisa [31]3 years ago
6 0
B I hope gn his helps you
lara [203]3 years ago
3 0
B is correct because the zero in 10.590 doesn't change the value of the number and 10.590 is equal to 10.59.

Hope this helps!
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I don't think i've been so confused ever, how do I solve this using long division?
tankabanditka [31]

Check the picture below.

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3 years ago
Is it possible to make a quadrilateral with any four dots as corners?
Elden [556K]

Answer:

Yes it is possible, given with 4 dots, lets say were set anywhere within a page or anywhere upon a circumference of a circle even. We can draw 4 straight lines to meet each corner and call this a quadrilateral.

Step-by-step explanation:

Squares, Rectangles and Rhombuses are all Parallelograms and squares and rectangles are regular quadrilaterals!

So any other 4 sided shape that is quadrilateral could be made.

The picture below shows all branches of quadrilaterals.

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3 years ago
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This table shows a family's monthly budget. What percentage of the budget is allocated for entertainment? Round to the nearest t
lutik1710 [3]

Answer:

A)4.1%

Step-by-step explanation:

First you need to add all the payments together to get your total.

1400+300+150+800+300+150+100+100+150+200=3650

Then you cross multiply and divide to get the percentage.

\frac{entertainment}{total} \frac{150}{3650}=\frac{x}{100}

When you cross multiply and divide x≈4.1

8 0
3 years ago
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Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

8 0
2 years ago
The table shows y as a function of x. Suppose a point is added to this table. Which choice gives a point that preserves the func
Hunter-Best [27]

Answer:

<em>A) (-5,7)</em>

Step-by-step explanation:

<u>Functions and Relations</u>

A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).

By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

\boxed{A)\ (-5,7)}

8 0
3 years ago
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