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3 years ago

Which is true? A 10.59 > 10.60 B 10.590 = 10.59 C 10.43 < 10.24 D 9.0005 = 9.0050

Mathematics

2 answers:

Allisa [31]3 years ago

6 0

B I hope gn his helps you

lara [203]3 years ago

3 0

B is correct because the zero in 10.590 doesn't change the value of the number and 10.590 is equal to 10.59.

Hope this helps!

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---- PLEASE HELP <3 .. with steps :( <3

Zielflug [23.3K]

1) 6, 18, 54

2) 5/3, 14/9, 41/27

3) 1.5, 2.5, 2.5

Step-by-step explanation:

The function that we have in this problem is

$g(x)=3x$

We want to find the first 3 iterations.

The initial value is:

x = 2

To find the value of the 1st iteration, we just substitute this value into the expression of the function, and we get:

$g_1(x)=3x=3\cdot 2 = 6$

The to find the value of the 2nd iteration, we just substitute this value into the expression of the function, and we get:

$g_2(x)=3\cdot g_1(x)=3\cdot 6 = 18$

Finally, the 3rd iteraction is given by:

$g_3(x)=3g_2(x)=3\cdot 18=54$

Here in this problem the function that we have to use is

$g(x)=\frac{1}{3}x+1$

The initial value is

$x=2$

So the first iteration is given by

$g_1(x)=\frac{1}{3}\cdot 2 + 1 = \frac{5}{3}$

To find the 2nd iteration, we substitute this value into g(x) again:

$g_2(x)=\frac{1}{3}g_1+1=\frac{1}{3}\cdot \frac{5}{3}+1=\frac{5}{9}+1=\frac{14}{9}$

Finally, to find the 3rd iteration, we substitute this value into g(x) again:

$g_3(x)=\frac{1}{3}\cdot \frac{14}{9}+1=\frac{14}{27}+1=\frac{41}{27}$

The function in this problem is

$g(x)=-|x-2|+3$

The initial value is

x = 0.5

So, the first iteration is:

$g_1(x)=-1|0.5-2|+3=-1|-1.5|+3=-1\cdot 1.5 +3=-1.5+3=1.5$

The second iteration is given by

$g_2(x)=-|g_1-2|+3=-|1.5-2|+3=--0.5+3=2.5$

Finally, the 3rd iteration is

$g_3(x)=-|g_2-2|+3=-|2.5-2|+3=-0.5+3=2.5$

5 0

3 years ago

Which of the following terms is defined as a set of all points in a plane that are a given distance from a point?

Ira Lisetskai [31]

Answer:

hhhhhshshdhdhdshsjssjjsjdjdjd

7 0

3 years ago

Given the equation p = s Subscript 1 Baseline t minus 2 Subscript 2 Baseline t, which equation is solved for t? t = p (s Subscri

gulaghasi [49]

Answer:

Option C) is correct

That is t=StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

It also can be written as $t=\frac{p}{s_{1}-s_{2}}$

Step-by-step explanation:

Given equation can be written as below:

$p=s_{1}t-s_{2}t$

Now to solve the equation for t:

$p=s_{1}t-s_{2}t$

Taking common term t outside on RHS we get

$p=(s_{1}-s_{2})t$

$\frac{p}{s_{1}-s_{2}}=t$

Rewritting the above equation as below

$t=\frac{p}{s_{1}-s_{2}}$

Therefore option C) is correct

That is t=StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

It also can be written as $t=\frac{p}{s_{1}-s_{2}}$

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3 years ago

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