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JulsSmile [24]
3 years ago
5

Which is true? A 10.59 > 10.60 B 10.590 = 10.59 C 10.43 < 10.24 D 9.0005 = 9.0050

Mathematics
2 answers:
Allisa [31]3 years ago
6 0
B I hope gn his helps you
lara [203]3 years ago
3 0
B is correct because the zero in 10.590 doesn't change the value of the number and 10.590 is equal to 10.59.

Hope this helps!
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Show that f(2-3i) is a real number
densk [106]

Answer:

2 - 3i

is 2 - the square root of -9

2 -√-9

2 + √9

2 + 3 = 5

<em><u>Thank you (I dont know if these answers are  100% correct but I tried my best!)</u></em>

7 0
3 years ago
SQUARE ROOT OF 8<br><br>THANKS -,-​
sergey [27]

Answer:

it's 2

Step-by-step explanation:

square root of 8 is 2

5 0
3 years ago
Read 2 more answers
On day two of a study on body temperatures, 106 temperatures were taken. Suppose that we only have the first 10 temperatures to
NemiM [27]

Answer:

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.2622

The margin of error is:

M = T*s = 2.2622*0.3 = 0.68

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF

The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

4 0
3 years ago
1. Darnell reads at a constant rate
JulsSmile [24]

Answer:

Darnell can read 1,715 words in 7 minutes

Step by step Explanation:

1. I need to find out how many words he reads in 1 minute. Divide 735 by 3, my answer is 245

245

______

3)735

6 bring down the 3 to make 13

-_____

1 3

12 bring down the 5 to make 15

-______

1 5

15

___________

0

2. multiply 735 by 2 cause he reads 735 words in 3 minutes and we are tryna find out how many words he reads in 7 minutes. 3×2=6, so 735+735 (735×2) equals 1470

3. Add 245, for that extra minute that we missed. my answer is 1,715 words in 7 minutes

8 0
3 years ago
Use the graph of △ABC with midsegments DE, EF and DF. Show that EF is parallel to AC and that EF=1/2 AC
Vinvika [58]

According to the midsegment theorem, the midsegments are parallel to

and half the length of the opposite side.

The completed statement are as follows;

  • Because the slopes of \overline{EF} and \overline{AC} are both<u> -4</u>, \overline{EF} ║ \overline{AC}
  • EF = \underline{\sqrt{17}} and AC = \underline{2 \cdot \sqrt{17} }
  • Because \underline{\sqrt{17} } = \underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17} }, EF = \frac{1}{2} \cdot AC

<u />

Reasons:

From the given graph of ΔABC, we have;

Coordinates of the points <em>A</em>, <em>B</em>, and <em>C </em>are; A(-5, 2), B(1, -2), and C(-3, -6)

The coordinates of the point D and E on \mathbf{\overline{DE}} are; D(-4, -2), and E(-2, 0)

The coordinates of the point F is; F(-1, -4)

  • Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

\displaystyle Slope \ of \ line \ \overline{AC} = \mathbf{\frac{(-6) - 2}{-3 - (-5)}  = \frac{-8}{2}} = -4

\displaystyle Slope \ of \ line \ \overline{EF} = \frac{0 - (-4)}{-2 - (-1)}  = \frac{4}{-1} = -4

  • Length \ of \ segment,\ l = \sqrt{\left (x_{2}-x_{1}  \right )^{2}+\left (y_{2}-y_{1}  \right )^{2}}

Length of EF  = √((-1 - (-2))² + (-4 - 0)²) = √(17)

Length of AC = √((-3 - (-5))² + (-6 - 2)²) = √(4 × 17) = 2·√(17)

Therefore, we have;

Because the slope of \mathbf{\overline {EF}} and \mathbf{\overline {AC}} are both , <u>-4</u>, \overline {EF} ║ \overline {AC}. EF = \underline{\sqrt{17}}, and AC

= \underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}},. Because \underline{\sqrt{17}} = \underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}, EF =\mathbf{ \frac{1}{2} AC}

Learn more about midsegment theorem of a triangle here:

brainly.com/question/7423948

8 0
2 years ago
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