ILL GIVE BRAINLIEST PLEASE HELP ME
2 answers:
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Answer:
14.63% probability that a student scores between 82 and 90
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a student scores between 82 and 90?
This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So
X = 90
has a pvalue of 0.9649
X = 82
has a pvalue of 0.8186
0.9649 - 0.8186 = 0.1463
14.63% probability that a student scores between 82 and 90
Answer:
The commission would be $ 920.
Step-by-step explanation:
Given,
Sales in 1997 = $ 9500,
Since, there is a commision of 8 % on the first $ 7500 of sales, 16% on the next $ 7500 of sales, and 20% on sales over $ 15,000,
If x represents the total sales,
Commission for x ≤ 7500 = 8% of x = 0.08x,
Commission for 7500 < x ≤ 15000 = 8% of 7500 + 16% of (x-7500)
= 600 + 0.16(x-7500),
Commission for 7500 < x ≤ 15000 = 8% of 7500 + 16% of 7500 + 20% of (x-15000)
= 600 + 1200 + 0.20(x-15000)
= 1800 + 0.20(x-15000)
Thus, the function that shows the given situation,
Since, 9500 lies between 7500 and 15000,
Therefore, the commission would be,
f(9500)= 600 + 0.16(9500 - 7500) = 600 + 320 = $ 920