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Akimi4 [234]
3 years ago
7

Kenwyn is making flower arrangements for invent the table shows the number of flower arrangement F can make an M minutes which e

quation represents the relationship between the number of flower arrangement she can make in the time in minutes it takes her to make a flower arrangements
Mathematics
2 answers:
NARA [144]3 years ago
8 0

Answer:

b

Step-by-step explanation:

CaHeK987 [17]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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The function f(x)= 3(1.4)' gives the length (in inches) of an image after being enlarged by 10% x times.
kondaur [170]

Answer:

3.99 inches

Step-by-step explanation:

<u><em>The correct question is</em></u>

The function f(x) = 3(1.1)^x gives the length (in inches) of an image after being enlarged by 10% x times.

What is the length of the image after it has been enlarged 3 times? Round your answer to the nearest  hundredth

we have

f(x)=3(1.1)^x

This is a exponential growth function

where

f(x) represent the length (in inches) of an image

x is the number of times the image is enlarged

so

For x=3

substitute in the exponential equation

f(x)=3(1.1)^3=3.99\ in

4 0
3 years ago
Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are
jasenka [17]

Answer:

The indicated confidence interval for the difference between the two population means is  (-1.5159, 7.5159)

Step-by-step explanation:

Let the drying times of type A be the first population and the drying times of type B be the second population. Then

We have small sample sizes n_{1} = 11 and n_{2} = 9, besides \bar{x}_{1} = 71.5, s_{1} = 3.4 , \bar{x}_{2} = 68.5 and s_{2} = 3.6. Therefore, the pooled

estimate is given by  

s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(11-1)(3.4)^{2}+(9-1)(3.6)^{2}}{11+9-2} = 12.1822

The 99% confidence interval for the true mean difference between the mean drying time of type A and the mean drying time of type B is given by

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{11}+\frac{1}{9}}, i.e.,

(71.5-68.5)\pm t_{0.005}(3.4903)\sqrt{\frac{1}{11}+\frac{1}{9}}

where t_{0.005} is the 0.5th quantile of the t distribution with (11+9-2) = 18 degrees of freedom. So

3\pm(-2.8784)(3.4903)(0.4495), i.e.,

the indicated confidence interval for the difference between the two population means is  (-1.5159, 7.5159)

5 0
3 years ago
3 10/15 - 1 12/15 what is difference
Montano1993 [528]

Answer:

28/15

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

3 0
3 years ago
What is 5ft 3in - 5in=
zalisa [80]
5 ft 3 in - 5in = 4 ft 15 in - 5 in = 4ft 10 in



Answer:  4ft 10 in
5 0
3 years ago
Ariana just started a running plan where she runs 8 miles the first week and then
Alex

Answer: 12 miles

Step-by-step explanation:

Hi, to answer this question we have to write a growth equation.

Total miles = 8 (1 +0.05)^9 = 12.41 =12 miles

Where 8 is the initial miles she run, since is increasing each week by 5% we have to multiply it by 1+ percent increase rate in decimal form (1+0.05) to 9th power (number of weeks)

She will run 12 miles in 9 weeks.

6 0
4 years ago
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