3 years ago

5x+9-2x-7y What is the coefficient of the y term?

Mathematics

1 answer:

NARA [144]3 years ago

7 0

Coefficient = number of so coefficient of y term = number of y's

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On a coordinate plane, point A is located at (7, 4), and point B is located at (-8, 4). What is the distance between the two poi

wel

Answer:

Solution given;

A(x1,y1)=(7,4)

B(x2,y2)=(-8,4)

distance AB=?

we have

d= $\sqrt{(x2-x1) ²+(y2-y1) ²}$

AB= $\sqrt{(-8-7)²+(4-4)²}$

AB=15 units

the distance between the two points is 15 units.

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2 years ago

PLEASE HELP ANSWER CORRECTLY !!!!!!!!!!!!!! WILL MARK BRIANLIEST !!!!!!!!!!!!!!

Nina [5.8K]

Hello, hehelol12.

The length of PR is the same as TR.

Length of PR = 11.

The measure of angle PQR is the same as angle RST.

Measure of angle PQR = 39

I hope this helps you out!

PS. Brainliest would be appreciated. :)

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2 years ago

Please help with #12 im confused<br> that is the key but i dont get it

Svetllana [295]

Given Equation

$\boxed{ \tt \: (8 \sqrt{3} - 2 \sqrt{2} )(8 \sqrt{3} + 2 \sqrt{2})}$

Step by step expansion:

$\dashrightarrow \sf \: (8 \sqrt{3} - 2 \sqrt{2} )(8 \sqrt{3} + 2 \sqrt{2})$

$\\ \\$

$\dashrightarrow \sf \: (8 \sqrt{3})^{2} - (2 \sqrt{2} {)}^{2}$

Reason:

(a + b)(a - b) = a²- b²

$\\ \\$

$\dashrightarrow \sf \: (8 {}^{2} \times { \sqrt{3} }^{2} )- (2 \sqrt{2} {)}^{2}$

$\\ \\$

$\dashrightarrow \sf \: (64 \times 3 ) - (2 \sqrt{2} {)}^{2}$

$\\ \\$

$\dashrightarrow \sf \: (64 \times 3 ) - (2 {}^{2} \times \sqrt{2} {}^{2} {)}$

$\\ \\$

$\dashrightarrow \sf \: 192- 8$

$\\ \\$

$\dashrightarrow \sf \: 184$

$\\ \\$

~BrainlyVIP ♡

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2 years ago

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If BC=2x-3 and AC=2x+10, find the length of AB

Anettt [7]

Answer:

Step-by-step explanation:

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2 years ago

describe how the location of the vertex of the angle determines the process of finding the angle measures associated with that a

LekaFEV [45]

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Step-by-step explanation:

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3 years ago