3 years ago

Twice a number, decreased by nineteen

Mathematics

1 answer:

Vinil7 [7]3 years ago

8 0

That would be 2n-19 you dont acctually get a answer

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shepuryov [24]

Answer:

$\frac{3}{2}$

Step-by-step explanation:

Given the expression:

$\frac{n+3}{2n-6} \div \frac{n+3}{3n-9}$

We are to find the quotient as shown:

$= \frac{n+3}{2n-6} \div \frac{n+3}{3n-9} \\\\= \frac{n+3}{2n-6} \times \frac{3n-9}{n+3} \\\\= \frac{n+3}{n+3} \times \frac{3n-9}{2n-6}\\\\= 1 \times \frac{3(n-3)}{2(n-3)}\\\\= 1 \times \frac{3}{2} \\\\= \frac{3}{2}$

Hence the correct answer is $\frac{3}{2}$

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No matter what number you substitute for y, this equation will be untrue.

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Hey guys ! Can anyone help me with these problems please and thanks

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at we both use canvas let's gooo

Step-by-step explanation:

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