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3 years ago

5. Melissa bought a pencil for $0.34, an eraser

Mathematics

1 answer:

kiruha [24]3 years ago

8 0

the reasonable estimate is 154

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Solve the equation. y + 13 = 10

docker41 [41]

Y = -3

T = -4

7x - 14

X = 4

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3 years ago

What is the factor tree for 16 and 20

mrs_skeptik [129]

20: 1,24,5,20

16: 1,2,16

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3 years ago

5x + 7 = 2 what is X A.x = -1 B.x = 1 C.x = 6 D.x = -6

ohaa [14]

Answer:

-1

Step-by-step explanation:

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3 years ago

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5a/5a+5 x 10a +10/10

DIA [1.3K]

Answer: 50a+2

Step-by-step explanation:

1. Simplify 5a5a\5a5a to 1.

1+5×10a+10

2.Simplify 5×10a to 50a.

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3.Cancel 10.

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4. Collect like terms.

50a+(1+1)

5. Simplify.

50a+2

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3 years ago

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Look at the picture

Sonbull [250]

$\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \frac{9(|x-8|)}{9} < \frac{36}{9} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}$

$\underline{\boldsymbol{\sf{Answer}}}$

$\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }$

$\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \ correct \ option}} \ \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}$

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2 years ago