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dangina [55]
3 years ago
13

5. Melissa bought a pencil for $0.34, an eraser

Mathematics
1 answer:
kiruha [24]3 years ago
8 0

the reasonable estimate is 154

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Please help e and my sister want to go somewhere but we cant because of this​
gtnhenbr [62]

Answer:

1 5/12 lb

Step-by-step explanation:

This is a subtraction problem.

He started with 4 2/3 lb and used 3 1/4 lb, so you need to subtract 3 1/4 lb from 4 2/3 lb.

Notice that the fractions do not have the same denominator, so we need a common denominator and equivalent fractions.

We start with the

subtraction below

       4 2/3

  -    3 1/4

---------------

The least common denominator of 3 and 4 is 12. 12/3 = 4, and 12/4 = 3, so we get equivalent fractions with the common denominator 12.

We use the LCD to get

the subtraction below

       4 8/12

  -    3 3/12

----------------

Now we subtract the whole numbers and the fractions.

       4 8/12

  -    3 3/12

----------------

       1 5/12

Answer: 1 5/12 lb

8 0
3 years ago
Suppose that you want to estimate average income in a population. If the standard deviation of income in the population is $1,00
Alik [6]

Answer:

2401

Step-by-step explanation:

Given that we want to estimate average income in a population.

The standard deviation of income in the population is $1,000

We want confidence interval around our estimate to be +/- $40

i.e Margin of error = 40

We know that margin of error = Std error * Z critical for 95%

i.e. 40 = 1.96 * std error

Std error = \frac{std dev}{\sqrt{n} } \\=\frac{1000}{\sqrt{n} }

Together we get

40=1.96(\frac{1000}{\sqrt{n} } )\\\sqrt{n} =\frac{1000*1.96}{40} \\=49\\n=2401\\

3 0
3 years ago
What is the area of a trapezoid if the base is 5, 17, 5 and height is 4
Monica [59]

Answer:3

Step-by-step explanation: becusause it is very easy man

3 0
3 years ago
Read 2 more answers
Hich function has a range of {y|y ≤ 5}?
marshall27 [118]

Answer:

f(x)=-(x-4)^{2}+5

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

if a>0 -----> the parabola open upward (vertex is a minimum)

if a<0 -----> the parabola open downward (vertex is a maximum)

<u>Verify each case</u>

case A) f(x)=(x-4)^{2}+5

The vertex is the point (4,5)

a=1

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [5,∞)

y\geq5

case B) f(x)=-(x-4)^{2}+5

The vertex is the point (4,5)

a=-1

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,5]

y\leq 5

case C) f(x)=(x-5)^{2}+4

The vertex is the point (5,4)

a=1

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [4,∞)

y\geq4

case D) f(x)=-(x-5)^{2}+4

The vertex is the point (5,4)

a=-1

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,4]

y\leq 4

4 0
3 years ago
What is a solution for this problem 60-36/3*4
Ksivusya [100]
The answer is 12
I hope I helped! 
4 0
3 years ago
Read 2 more answers
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