Question

A class of 222 students went on a field trip. They took 9 vehicles, some cars and some me buses. find the number of cars and the number of busses they took if each car holds 4 students and each bus holds 35 students ​

Answer 1

Answer:

There were 3 cars and 9 buses used for the field trip.

Step-by-step explanation:

Let the number of cars be x

and Number of buses be y.

Total number of vehicles used = 9

Hence,

$x+y=9 \ \ \ \ equation \ 1$

Also

Each Car carries students = 4

Each Bus carries students = 35

Total Students = 222

Hence,

$4x+35y =222 \ \ \ \ equation \ 2$

Now multiplying equation 1 by 4 we get;

$4(x+y)= 4\times 9 \\4x+4y = 36 \ \ \ \ \ equation \ 3$

Now Subtracting equation 3 from equation 2 we get;

$4(x+y)= 4\times 9 \\[tex](4x+35y)-(4x+4y) =222-36\\4x+35y-4x-4y=186\\31y = 186\\y = \frac{186}{31} = 6$

Now y = 6

∴ x + y = 9 (Given)

x + 6 = 9

x = 9 - 6

x = 3

Hence, There were 3 cars and 9 buses used for the field trip.