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Answer:
- (3, 5), (1, 2) and (5, 1)
Step-by-step explanation:
Make three systems with pairs of lines and solve them to work out the vertices.
1) <u>Line 1 and line 2</u>
<u>Double the second equation and subtract equations:</u>
- -3x + 2y - 2(2x + y) = 1 - 2(11)
- -3x - 4x = 1 - 22
- -7x = - 21
- x = 3
<u>Find y:</u>
- 2*3 + y = 11
- 6 + y = 11
- y = 11 - 6
- y = 5
The point is (3, 5)
2) <u>Line 1 and line 3</u>
<u>Triple the second equation and add up equations:</u>
- -3x + 2y + 3(x + 4y) = 1 + 3(9)
- 2y + 12y = 1 + 27
- 14y = 28
- y = 2
<u>Find x:</u>
- x + 4*2 = 9
- x + 8 = 9
- x = 1
The point is (1, 2)
3) <u>Line 2 and line 3</u>
<u>Double the second equation and subtract the equations:</u>
- 2x + y - 2(x + 4y) = 11 - 2(9)
- y - 8y = 11 - 18
- - 7y = - 7
- y = 1
<u>Find x:</u>
- x + 4*1 = 9
- x + 4 = 9
- x = 5
The point is (5, 1)
Step 1. Simplify 10/3b to 10b/3
12/5(10b/3 + 15/4)
Step 2. Distribute
8b + 9
Answer:
NO because 7+5=12
The sum must be larger (not equal to) the longest side. If it's exactly the same, there's no room to for the shorter two sides to angle up to form a triangle.
