Answer:
Step-by-step explanation:
Given: In a parallelogram ABCD, diagonals intersect at O and ar(ABCD) is 
.
We need to find the area of triangle AOB.
We know that each diagonal divide the parallelogram in two equal parts and diagonals bisect each other.
It means both diagonals divide the parallelogram in 4 equal parts.
Hence, the values of ar(AOB) is .
Answer:
it is true :)
Step-by-step explanation:
1st number: 0
2nd number: 17
Answer
Step-by-step explanation:
3x+2y=34 x is the first number, y is the second.
1/2x+2y=34 multiply each number by two to get rid of the integer by the variable x.
x+4y=68 solve for x.
x=68-4y add this into the first equation to solve for variable y.
3(68-4y)+2y=34 solve for y.
204-10y=34
-10y= -170
y=17
now to solve for x
x= 68-4(17)
x= 0
<span>Find the area of two sides (Length*Height)*2 sidesFind the area of adjacent sides (Width*Height)*2 sidesFind the area of ends (Length*Width)*2 ends<span>Add the three areas together to find the surface area</span></span>
